Question

The place kicker on a football team kicks a ball from ground level with an initial speed of 4.00 m/s at an angle of 29.0° above the horizontal. How long is the ball in the air, in seconds, before it lands on the ground again? You may neglect air resistance.

Answer 1

Answer:

0.4 s

Explanation:

The time that the ball is in the air can be found with the next formula:

$time = t = \frac{2v_{o}sen\beta}{g}$

where $v_{o}$ is the initial velocity of the ball, in this case:

$v_{o}=4.00 m/s$

β is the angle: β = 29.0°

And g is the acceleration of gravity: $g=9.81m/s^2$

Replacing all the values to find t, we have:

$time = t = \frac{2(4m/s)sen(29)}{9.81m/s^2} = 0.4s$

Thus, the ball is 0.4s in the air.