Answer:
The actual elevation angle is 12.87 degrees
Explanation:
In the attachment you can clearly see the situation. The angle of elevation as seen for the scuba diver is shown in magenta, we conclude that
.
Using Snell's Law we can write:
![n_1\sin(\theta_1)=n_2\sin(\theta_2)](https://tex.z-dn.net/?f=n_1%5Csin%28%5Ctheta_1%29%3Dn_2%5Csin%28%5Ctheta_2%29)
,
Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.
We thus have:
![\sin(\theta_1)=n_2\sin(\theta_2)=1.333\sin(47)](https://tex.z-dn.net/?f=%5Csin%28%5Ctheta_1%29%3Dn_2%5Csin%28%5Ctheta_2%29%3D1.333%5Csin%2847%29)
. Calling
the actual angle of elevation, we get from the picture that
Explanation:
Light is clearly affected by gravity, just think about a black hole, but light supposedly has no mass and gravity only affects objects with mass. On the other hand, if light does have mass then doesn't mass become infinitely larger the closer to the speed of light an object travels.
Answer:
h = 9.57 seconds
Explanation:
It is given that,
Initial speed of Kalea, u = 13.7 m/s
At maximum height, v = 0
Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :
![v=u-gt](https://tex.z-dn.net/?f=v%3Du-gt)
![u=gt](https://tex.z-dn.net/?f=u%3Dgt)
![t=\dfrac{u}{g}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bu%7D%7Bg%7D)
![t=\dfrac{13.7}{9.8}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B13.7%7D%7B9.8%7D)
t = 1.39 s
Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :
![h=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=h%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Here, a = -g
![h=ut-\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=h%3Dut-%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![h=13.7\times 1.39-\dfrac{1}{2}\times 9.8\times (1.39)^2](https://tex.z-dn.net/?f=h%3D13.7%5Ctimes%201.39-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.8%5Ctimes%20%281.39%29%5E2)
h = 9.57 meters
So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.
Answer:
Torque, ![\tau=34.6\ N.m](https://tex.z-dn.net/?f=%5Ctau%3D34.6%5C%20N.m)
Explanation:
It is given that,
Length of the wrench, l = 0.5 m
Force acting on the wrench, F = 80 N
The force is acting upward at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. We need to find the torque is applied to the nut. We know that torque acting on an object is equal to the cross product of force and distance. It is given by :
![\tau=Fr\ sin\theta](https://tex.z-dn.net/?f=%5Ctau%3DFr%5C%20sin%5Ctheta)
![\tau=80\times 0.5\ sin(60)](https://tex.z-dn.net/?f=%5Ctau%3D80%5Ctimes%200.5%5C%20sin%2860%29)
![\tau=34.6\ N.m](https://tex.z-dn.net/?f=%5Ctau%3D34.6%5C%20N.m)
So, the torque is applied to the nut is 34.6 N.m. Hence, this is the required solution.
The formula that can be used to obtain a convergent series is given by;
a/1 – r.
<h3>What is a series?</h3>
In mathematics, we define a series as sum of numbers which could be convergent or divergent. In a convergent series, the summation of the numbers approaches a given value.
The formula that can be used to obtain a convergent series is given by;
a/1 – r.
Learn more about a convergent series:brainly.com/question/15415793?
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