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andrew-mc [135]
3 years ago
9

Question 2

Chemistry
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

I want to say its Lonic Bonding.

Explanation:

Ionic bonding is the complete transfer of valence electron(s) between atoms.

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3 years ago
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. How many grams of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide? ____Cl
dlinn [17]

Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.

Explanation:

The balanced chemical reaction is;

Cl_2+MgBr_2\rightarrow MgCl_2+Br_2

Cl_2 is the limiting reagent as it limits the formation of product and MgBr_2 is the excess reagent.

According to stoichiometry :

1 mole of Cl_2 produces = 1 mole of MgCl_2

Thus 2 moles of Cl_2 will produce=\frac{1}{1}\times 2=2moles  of MgCl_2

 Mass of MgCl_2=moles\times {\text {Molar mass}}=2moles\times 95g/mol=190g

Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide

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3 years ago
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What is the theoretical yield of SO3 produced by 8.96 g of S?
Virty [35]

Answer: Theoretical yield of SO_3 produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles

The balanced chemical equation is:  

2S+3O_2\rightarrow 2SO_3  

According to stoichiometry :

2 moles of S produce =  3 moles of SO_3

Thus 0.28 moles of S will produce=\frac{3}{2}\times 0.28=0.42moles  of SO_3  

Mass of SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g

Thus theoretical yield of SO_3 produced by 8.96 g of S is 33.6 g

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