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pashok25 [27]
3 years ago
5

What other objects are often arranged by there properties

Chemistry
1 answer:
Trava [24]3 years ago
4 0

Answer:

other than the periodic table, are often arranged by their properties

Explanation:

Money, they are arranged by how big or small they are, like coins, with pennies, dimes, and quarters.

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Explain how both analytical and creative problem-solving strategies can be applied to the following scenario. Jeff notices that
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Answer: They can be apllied to the senario he can pettition or he can use bigger bags those are just a couple of ideas.

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3 years ago
___in Earth’s___ is the up and down movements of plastic-like material within that layer.
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It's D 
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3 years ago
How many grams of sulfur trioxide are produced 18 mol O2 react with sufficient sulfur? Show all your work S8 +12O 2> 8SO3
SOVA2 [1]

Answer:

m_{SO_3}=2.31x10^4gSO_3

Explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

S_8 +\frac{1}{2} O_2 \rightarrow 8SO_3

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m_{SO_3}=18molO_2*\frac{8molSO_3}{1/2molO_2} *\frac{80.06gSO_3}{1molSO_3} \\\\m_{SO_3}=23,057.3gSO_3=2.31x10^4gSO_3

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7 0
3 years ago
Explain the components of Petroleum and their uses.
RideAnS [48]
<h2>answer:</h2>

Various Constituents of Petroleum and their Uses

Constituents of Petroleum

Kerosene

uses➪ Fuel for stoves, in lamps and as aviation fuel for jet aircrafts

Constituents of Petroleum

LPG

uses➪ Fuel for home and industry

Constituents of Petroleum

Lubricating oil

uses➪Used for Lubrication in machines and engines

Constituents of Petroleum

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8 0
3 years ago
2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock
RSB [31]

Answer:

The NaCl concentration will be 0.03 M.

Explanation:

Given data:

Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)

Initial concentration = M₁= 0.5894 M

Final volume = V₂= 1.20 L

Final concentration = M₂= ?

Solution:

By diluting the solution volume of solution will increase while number of moles of solute remain the same.

Formula:

Initial concentration × Initial volume  = Final concentration × Final volume

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 0.5894 M × 0.05698 L / 1.20 L

M₂ = 0.0336 M /1.20  

M₂ = 0.03 M

3 0
4 years ago
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