Answer:
Normalidad = 4N
%p/V = 27.6%
Explanation:
La solución 2M de carbonato de potasio contiene 2moles de carbonato por litro de solución. La normalidad son los equivalente de carbonato de potasio (2eq/mol) por litro de solución:
2moles * (2eq/mol) = 4eq / 1L = 4N
El porcentaje peso volumen es el peso de carbonato en gramos dividido en el volumen en mL por 100:
%p/V:
Masa K2CO3 -Masa molar: 138.205g/mol-
2moles * (138.205g/mol) = 276g K2CO3
Volumen:
1L * (1000mL/1L) = 1000mL
%p/V:
276g K2CO3 / 1000mL * 100
<h3>%p/V = 27.6%</h3>
H₂SO₃ is weaker acid than H₂SO₄.
The bonding power of an acid is typically influenced by the size of the "SO₄" atom; the smaller the "SO₄" atom, the stronger the H-A bond. The atoms get larger and the bonds get weaker as you proceed down a row in the Periodic Table, strengthening the acids.
<h3>Describe acid.</h3>
The term "acid" refers to any molecule or ion that can donate a proton (a Brnsted-Lowry acid) or establish a covalent bond with an electron pair (a Lewis acid). The first class of acids is the proton donors, also known as Brnsted-Lowry acids.
Its chemical name is lysergic acid diethylamide, or LSD as it is more often known. Because it has a potent hallucinogenic impact, using it could alter how you see the world and its objects. The effects of LSD are referred to as tripping.
The term "acid" is frequently used to denote aqueous solutions of acids with a pH lower than 8, even though the technical meaning of the term only pertains to the solute.
To learn more about acid visit:
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Answer:
<h2>pH = 4.44 </h2>
Explanation:
The pH of a substance can be found by using the formula
![p H = - log[ H^{ + } ]](https://tex.z-dn.net/?f=p%20H%20%20%3D%20%20-%20%20%20log%5B%20H%5E%7B%20%2B%20%7D%20%20%5D)
where [ H+ ] is the hydrogen ion concentration of the solution
From the question
[ H + ] = 3.60 × 10^-5 M
So the pH is

We have the final answer as
<h3>pH = 4.44 </h3>
Hope this helps you
I would say diamond, because it consists only of carbon
Molarity is defined as the number of moles of solute in 1 L of solution
mass fo KCl in the solution is - 5.0 g
number of moles of KCl - 5.0 g/ 74.5 g/mol = 0.067 mol
number of moles of KCl in 100 mL - 0.067 mol
therefore number of KCl moles in 1 L - 0.067 / 100 mL x 1000 mL = 0.67 M
molarity of KCl is 0.67 M