Answer:
9t^2+(t+2)^2
Step-by-Step:
t is 9 X t, or the product of 9 and t. ^2 is squared while + is increased t+2 is the sum of t and t. the ^2 after the parenthesis is indicating the "square of t and 2"
10, 20w, 2w, and we are factors of 20w and 40wz
Answer:
0.319 m³/s
Step-by-step explanation:
Data provided:
Initial volume in the river = 255 m³
Final volume required in the storage = 325 m³
Average outflow = 0.30 m³/s
Duration for raising the level = 1 hour = 3600 seconds
Now,
The actual volume required to raise the volume to 325 m³
= Final volume - Initial volume
= 325 m³ - 255 m³
= 70 m³
also,
the amount of outflow in 1 hour = Average rate of outflow × Time
= 0.30 m³/s × 3600 s
= 1080 m³
Therefore,
the total volume required = 1080 m³ + 70 m³ = 1150 m³
Now,
the average rate of inflow required =
=
= 0.319 m³/s
I think that the answer is -1/6. I got this by subtracting 3 on both sides according to the order of operations and got -1. Next, I divided 6 on both sides to undo the multiplication. Since you can't do 1 divided by 6, you can leave it as a fraction which is -1/6.
Independent because what you get in the first one doesn't effect the second