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ankoles [38]
3 years ago
6

To understand the electric potential and electric field of a point charge in three dimensions Consider a positive point charge q

, located at the origin of three-dimensional space. Throughout this problem, use k in place of 14?
Physics
1 answer:
Liula [17]3 years ago
5 0

Answer:

The magnitude of the electric field at distance r from the point charge q is \dfrac{kq}{r^2}

Explanation:

Suppose, Find E(r), the magnitude of the electric field at distance r from the point charge q.

We know that,

The electric field is proportional to the point charge and inversely proportional to the square of the distance from the charge point .

In mathematically,

E=\dfrac{kq}{r^2}

Where, q = charge point

R = distance from charge point

Hence, The magnitude of the electric field at distance r from the point charge q is \dfrac{kq}{r^2}

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What is a discussion?
kap26 [50]

Answer:

um, when you talk with other people about stuff. (I'm not trying to sound like a smarta s s I'm just giving a definition...)

Explanation:

7 0
3 years ago
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A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh
Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 rad/sec^2

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius r=\frac{d}{2}=\frac{1.63}{2}=0.815m

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec

(b) We know that linear speed is given by

v=r\omega =0.815\times 8.362=6.815m/sec

(c) We have given final angular velocity \omega _f=675rev/min

And \omega _i=79.9rev/min

Time t = 63 sec

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2

(d) Change in angle is given by

\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev

7 0
3 years ago
A block of mass m=1.2 kg is held at rest against a spring with a force constant k=730N/m. Initially the spring is compressed a d
igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

= 1/2 x 730 d²

= 365 d²

This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

= 1/2 x 1.2 x 2.3²

= 3.174 J

Loss of energy

= 365 d² - 3.174  

This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d ,   μ = coefficient of friction , m is mass of block , d is width of patch

= .44 x 1.2 x 9.8 x .05

= .2587 J

365 d² - 3.174   = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

5 0
3 years ago
The denizens of a distant planet live under an atmosphere made predominantly of CO2 which is a dispersive medium while attending
LuckyWell [14K]

Since the frequency of sound in a medium is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.

<h3>What is a dispersive medium?</h3>

A dispersive medium is a medium which spreads out or disperses a substance passing through it.

Since CO2 is a dispersive medium, it means sound waves passing through it would be dispersed based on wavelength.

The note of a sound depends on its frequency, the higher the frequency, the higher the note.

Frequency of sound is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.

Learn more about dispersion of sound at: brainly.com/question/781734

5 0
2 years ago
The speed of a wave is 2ms, and its wavelength 0.4 meters. What is the period of the wave?
AnnyKZ [126]

Answer:

5

Explanation:

6 0
2 years ago
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