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sergiy2304 [10]
3 years ago
6

A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 31.8 ◦C . In an attempt to cool the liquid, wh

ich has a mass of 161 g , 131 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 28.8 ◦C , find the mass of the remaining
Physics
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer:

Explanation:

mass of liquid m₁ = 161 g

temperature t₁ = 31.8

final temperature t₂ = 28.8

Let m g of ice melted to cool the liquid

heat gained = mass x latent heat of fusion + mass x loss of temp x s heat of water

= m x 80 + m x 1 x ( 31.8 - 28.8 ) ( latent heat of ice = 80 cals/g )

= 83 m

heat lost  = 161 x 1 x ( 31.8 - 28.8 ) ( specific heat of water = 1 cal / g / k )

= 161 x 3

heat lost = heat gained

83 m = 161 x 3

m = 5.82 g

mass of remaining ice = 131 - 5.82

= 125.18 g

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When the canoe leaked, the boat sank because it has a leak. The boat must have a strong base at its bottom to enable itself to float. If this is damaged, the water can now enter due to the hole thereby increasing the velocity of water coming in.

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2 years ago
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If 2.40 g of KNO3 reacts with sufficient sulfur (S8) and carbon (C), how much P-V work will the gases do against an external pre
creativ13 [48]

Answer:

-112.876J

Explanation:

In order to solve this question, we would need to incorporate Stoichiometry, which involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Here's a balanced equation for the reaction:

16KNO_3(s) + 24C(s) + S_8(s)    \to 24CO_2(g) + 8N_2(g) + 8K_2S(s)

Let us define P - V work as;

w_{pv} = - P_{external}  \triangle Volume

where  \triangle (Volume) = (V_{final} - V_{initial})

External pressure is given as  1.00atm , therefore the work solely depends on the change in volume and since the reactants are solids, none of the reactants contribute to the volume. Hence,  V_i = 0.

To find the volume of the products, we need to first find the amount of moles of the product made from  2.40_gKNO_3, using the molar mass of  KNO_3  which is 101.1032 g/mol  

2.40_gKNO_3 . {\frac{1molKNO_3}{101.1032_g}} = 0.0237molKNO_3

Now let us convert moles of  KNO_3  into moles of CO_2 and N_2  using the stoichiometric ratios from our balanced equation of the reaction.

0.0237molKNO_3 . {\frac{24molCO_2}{16molKNO_3}} = 0.0356molCO_2

0.0237molKNO_3 . {\frac{8molN_2}{16molKNO_3}} = 0.01185molN_2

K_2S is not factored into the volume calculation because it is a solid.

Now let us also convert the moles of  CO_2  and  N_2 into grams using their respective molar masses.

0.0356molCO_2 . {\frac{44.01_g}{1molCO_2}} = 1.567_gCO_2

0.01185molN_2 . {\frac{28.014_g}{1molN_2}} = 0.332_gN_2

We will now proceed to convert grams into volume using the density values provided.

1.567_gCO_2 . {\frac{1L}{1.830_g}} = 0.856LCO_2

0.332_gN_2 . {\frac{1L}{1.165_g}} = 0.285LN_2

Summing up the two volumes, we get the final volume

0.856L + 0.258L = 1.114L = V_f

Plugging everything into the w_{pv} equation, we get:

w_{pv} = -1atm(1.114L - 0L) = -1.114L.atm

Finally, let us convert L.atm into joules using the conversion rate of;

1L.atm = 101.325J\\-1.114L.atm. {\frac{101.325J}{1L.atm}} = -112.876J

7 0
3 years ago
What is the economic system in the united states?
AnnyKZ [126]

Answer:

A. Capitalist economy

Explanation:

The United States is a capitalist economy. Hope this helps, thank you !!

3 0
3 years ago
In this diagram, which force is represted by L?
Dmitry [639]
Answer is a) the force caused by the wend nag encountering wind and air.
8 0
3 years ago
The temperatureTdin degrees Fahrenheit in terms of the Celsius temperaturedis given by=Td+9/5d+32.The temperatureCvin degrees Ce
Shalnov [3]

Answer:

T_F=\frac{9}{5}(T_K-273)+32

Explanation:

Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula T_F=\frac{9}{5}T_C+32 and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula T_C=T_K-273, we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining T_F=\frac{9}{5}(T_K-273)+32.

7 0
3 years ago
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