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4 years ago

7

Explain how the cathode Ray was discovered?

1 answer:

lyudmila [28]4 years ago

8 0

Cathode rays carry electronic currents through the tube. Electrons were firstdiscovered as the constituents ofcathode rays. J.J. Thomson used thecathode ray tube to determine that atoms had small negatively charged particles inside of them, which he called “electrons.”

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A child is on a pogo stick. At the top of her jump, her kinetic energy (KE) = 0 J, her gravitational potential energy (GPE) = 10

krek1111 [17]

There would be 0 Potential energy, which eliminates A. There would be Spring energy, which eliminates C. So B and D are your 2 choices. Since the child is not moving just before the jump, there would be 0 Kinetic energy. So D.

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3 years ago

elixir [45]

Answer:

no le entiendo pero si me se la respuesta ya tu sabe ✨✨✨✨

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3 years ago

Which type of eclipse would you expect to see if the moon passes directly between earth and the sun?

Deffense [45]

C. A total lunar eclipse.

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3 years ago

Read 2 more answers

Consider this reaction:

Len [333]

Dilution of hcl because less no of mole of hcl would be reacting to form zncl2

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3 years ago

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If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r

kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)$

Energy absorbed by pork,E = $1.6\times 10^3 kJ$ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

$10\%=\frac{E}{Q}\times 100$

$Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ$

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = $-1.6\times 10^4 kJ$

Moles of propane burnt to produce Q energy =n

$n\times \Delta H_{rxn}=Q$

$n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol$

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

$\frac{1}{3}\times 7.83 mol=23.49 mol$ carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0

3 years ago