Answer:
![H3 = 25 * \frac{4}{5} * \frac{4}{5}* \frac{4}{5}](https://tex.z-dn.net/?f=H3%20%3D%2025%20%2A%20%5Cfrac%7B4%7D%7B5%7D%20%2A%20%5Cfrac%7B4%7D%7B5%7D%2A%20%5Cfrac%7B4%7D%7B5%7D)
Step-by-step explanation:
Given
![Initial\ Height =25](https://tex.z-dn.net/?f=Initial%5C%20Height%20%3D25)
![Rebound = \frac{4}{5}](https://tex.z-dn.net/?f=Rebound%20%3D%20%5Cfrac%7B4%7D%7B5%7D)
Required
Determine the height at the third rebound
At first rebound;
![H1 = 25 * \frac{4}{5}](https://tex.z-dn.net/?f=H1%20%3D%2025%20%2A%20%5Cfrac%7B4%7D%7B5%7D)
Second rebound
![H2 = 25 * \frac{4}{5}* \frac{4}{5}](https://tex.z-dn.net/?f=H2%20%3D%2025%20%2A%20%5Cfrac%7B4%7D%7B5%7D%2A%20%5Cfrac%7B4%7D%7B5%7D)
Third rebound
![H3 = 25 * \frac{4}{5} * \frac{4}{5}* \frac{4}{5}](https://tex.z-dn.net/?f=H3%20%3D%2025%20%2A%20%5Cfrac%7B4%7D%7B5%7D%20%2A%20%5Cfrac%7B4%7D%7B5%7D%2A%20%5Cfrac%7B4%7D%7B5%7D)
Hence; the equation is:
![H3 = 25 * \frac{4}{5} * \frac{4}{5}* \frac{4}{5}](https://tex.z-dn.net/?f=H3%20%3D%2025%20%2A%20%5Cfrac%7B4%7D%7B5%7D%20%2A%20%5Cfrac%7B4%7D%7B5%7D%2A%20%5Cfrac%7B4%7D%7B5%7D)
Solving further;
![H3 = 12.8\ ft](https://tex.z-dn.net/?f=H3%20%3D%2012.8%5C%20ft)
Answer:
The solution set we get is(x,y){(6/4 , 6)}....
Step-by-step explanation:
We have the system of equation:
y = 4x equation 1
8x + y= 18 equation 2
As we see that the first equation has a value of y. Now plug the value of y which is 4x in 2nd equation:
8x+y=18
8x+(4x)=18
12x=18
Divide both sides by 12.
12x/12= 18/12
x= 18/12
x= 6/4
Now plug the value x= 6/4 in equation 1.
y=4x
y=4(6/4)
4 will be cancelled out by 4
y = 6
The solution set we get is(x,y){(6/4 , 6)}....