Answer:
Step-by-step explanation:
Additive identity is 0.
step 3 used the additive identity property.
The <em><u>correct answer</u></em> is:
Explanation:
An exponential function is of the form
, where a is the initial population, b is 1 plus the amount of yearly change, and x is the number of years.
For our problem, a, the initial population, is 1500.
The yearly change is 6.3%; 6.3% = 6.3/100 = 0.063. Since it is decreasing, this is negative; 1+(-0.063) = 0.937.
We use t as the number of years.
This gives us
Answer:
B, C, D
Step-by-step explanation:
In this problem, the range is what the output, or y, can be. The origin, or the middie of the graph, is when x=0 and y=0. From the 10s on the screen, we can gather that 5 lines = a distance of 10 on the graph. Using this information, we can say
5 lines = distance of 10
divide both sides by 5 to find the distance for each line
1 line = distance of 2
The function goes from y=0 to three lines down, for a distance of 6. The range is therefore [-6,0] as all values from -6 to 0 on the y axis are included on the graph, including 0 and -6. In this range, -6, -2, and -1 are all included.
<h3>
Answer: 0.5</h3>
This is equivalent to the fraction 1/2
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Explanation:
The distance from A to B is 3 units. We can count out the spaces, or subtract the x coordinates of the two points and apply absolute value.
|A-B| = |-5-(-8)| = |-5+8| = |3| = 3
or
|B-A| = |-8-(-5)| = |-8+5| = |-3| = 3
We can say that segment AB is 3 units long.
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The distance from A' to B' is 1.5 units because...
|A'-B'| = |-2.5-(-4)| = |-2.5+4| = |1.5| = 1.5
or
|B'-A'| = |-4-(-2.5)| = |-4+2.5| = |-1.5| = 1.5
The absolute values ensure the distance is never negative.
We can say A'B' = 1.5
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Now divide the lengths of A'B' over AB to get the scale factor k
k = (A'B')/(AB)
k = (1.5)/(3)
k = 0.5
0.5 converts to the fraction 1/2.
The smaller rectangle A'B'C'D' has side lengths that are exactly 1/2 as long compared to the side lengths of ABCD.
Please be specific, how many people are in her class?
