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Arisa [49]
3 years ago
11

Wegnerkolmp or someone who can explain maths please I need a proper explanation

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Answer: 66 degrees

Explanation:

Check out the attached image below. Figure 1 is the original image without any additions or alterations. Then in figure 2, I extend segment BC to form a line going infinitely in both directions. This line crosses segment DE at point F as shown in the second figure.

Note how angles ABC and DFC are alternate interior angles. Because AB is parallel to DE (given by the arrow markers) this means angle DFC is also 24 degrees

Focus on triangle DFC. This is a right triangle. The 90 degree angle is at C.

So we know that the acute angles x and 24 are complementary. They add to 90. Solve for x

x+24 = 90

x+24-24 = 90-24

x = 66

That is why angle CDE is 66 degrees

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2 years ago
Using the Order of Operations, what is the solution to 2(4/2)2 - 15 + 6?
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Read 2 more answers
EASY POINTS Find the domain of the graphed function.
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Using it's concept, it is found that the domain of the graphed function is given as follows:

D. -4 \leq x \leq 2

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In this graph, x assumes values between -4 and 2, inclusive due to the closed circle, hence the domain is given by:

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1 year ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

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3 years ago
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