Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. Some points will be nice
Answer:
2370.0 contains 4 significant digits and Option (c) is correct .
1.20\times 10^{-3}\ contains\ three\ significant\ digit.
Option (b) is correct .
Step-by-step explanation:
Rules for finding significant digit .
1 : Non-zero digits are always significant.
2: Any zeros between two significant digits are significant .
3: Trailing zeros in the decimal number is also significant.
As the number given be 2,370.0.
= \frac{23700}{10}
Simplify the above
= 2370
Thus by using the rule given above.
2370.0 contains 4 significant digits.
Option (c) is correct .
As the number given be 0.00120 .
= \frac{120}{100000}
Simplify the above
= \frac{1.20}{1000}
= 1.20\times 10^{-3}
Thus by using the rule given above.
1.20\times 10^{-3}\ contains\ three\ significant\ digit.
Option (b) is correct .
Answer:
The part of the experiment that is set to compare data
Explanation:
The controlled variable is what stays constant throughout an experiment. You use the controlled variable to compare the new data to see what happened during whatever reaction you could say.
First, let's find the number of neutrons in Calcium-40. to find the number of neutrons, you need to take the atomic mass minus atomic number
neutrons in Calcium---> 40 - 20 (atomic number) = 20 neutrons
potassium-40---> 40- 19= 21
scandium-44----> 44- 21= 23
argon-38---------> 38- 18= 20
chlorine-36------> 36- 17= 19
the answer is argon-38
