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Liono4ka [1.6K]
3 years ago
7

Calculate the amount of heat required to completely sublime 96.0 g of solid dry ice (co2) at its sublimation temperature. the he

at of sublimation for carbon dioxide is 32.3 kj/mol.calculate the amount of heat required to completely sublime 96.0 g of solid dry ice (co2) at its sublimation temperature. the heat of sublimation for carbon dioxide is 32.3 kj/mol.
Chemistry
1 answer:
Debora [2.8K]3 years ago
8 0

The process in which slid phase is converted into gaseous phase directly without achieving the liquid phase is said to sublimation.

The heat required to completely sublime is calculated by the product of number of moles and heat of sublimation.

Heat required (Q)= number of moles (n)\times heat of sublimation   (1)

And, heat of sublimation of carbon dioxide is 32.3 kJ/mol

Number of moles of carbon dioxide = \frac{given mass in g}{molar mass}

= \frac{96.0 g}{44.01 g/mol}

= 2.18 moles

Now, put the values in formula (1)

Heat required (Q)= 2.18 moles\times 32.3 kJ/mol

= 70.414 kJ

Hence, heat required to completely sublime is 70.414 kJ

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Answer:

C)52g KCl in 100g water at 80°C

Explanation:

A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.

A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.

From the solubility curve in the attachment below:

A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.

B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.

C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.

D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.

7 0
3 years ago
How many grams of H2O can be made from the combustion of 3.75 liters of C7H14 and an excess of O2 at STP?
Kitty [74]

Answer:

21.10g of H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C7H14 + 21O2 —> 14CO2 + 14H2O

From the balanced equation above, 2L of C7H14 produced 14L of H2O.

Therefore, 3.75L of C7H14 will produce = (3.75 x 14)/2 = 26.25L of H2O.

Next, we shall determine the number of mole of H2O that will occupy 26.25L at stp. This is illustrated below:

1 mole of a gas occupy 22.4L at stp

Therefore, Xmol of H2O will occupy

26.25L i.e

Xmol of H2O = 26.25/22.4

Xmol of H2O = 1.172 mole

Therefore, 1.172 mole of H2O is produced from the reaction.

Next, we shall convert 1.172 mole of H2O to grams. This is illustrated below:

Number of mole H2O = 1.172 mole

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O =..?

Mass = mole x molar mass

Mass of H2O = 1.172 x 18

Mass of H2O = 21.10g

Therefore, 21.10g of H2O is produced from the reaction.

3 0
3 years ago
How to find limiting reagent
Nookie1986 [14]
The reagent which limits the reaction is called limiting reagents.

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For example:- N2+3H2gives 2NH3.so here nitrogen limits the reaction.

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cohesion-tension

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