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wolverine [178]
3 years ago
6

The fare for an Uber is $5 per trip plus $0.50 per mile. The fare for the trip from the airport to the school center was $11.50.

Write and solve an equation to find out how many miles the trip is from the airport to the airport to the school center.
Please answer quickly, will be giving out brainliest!
Mathematics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

13 miles

Step-by-step explanation:

The fare for the Uber

Cost= 5+ .5 m  

where m is the number of miles

We spent 11.50

11.50 = 5 + .5 m

Subtract 5 from each side

11.5 -5 = 5+.5m -5

6.50 = .5 m

Divide by .5 on each side

6.5/.5 = .5m/.5

13 = m

We went 13 miles

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Suppose that the times it takes adult women to run a mile are normally distributed with an unknown mean and standard deviation.
Inga [223]

Answer:

Step-by-step explanation:

8 0
3 years ago
Please help I'm stuck on this questions thanks
polet [3.4K]
So its asking for basically the percentage of the first number out of the second. 

3. 25/50 = 50%
4. 125/75 = 167%
5. 32/28 = 114%
6. 7/10 = 70%


Hope this helped!  :)
6 0
3 years ago
B.
Helen [10]

Answer:

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

Step-by-step explanation:

The given figure consists of three triangles

1. ΔUJN, 2. ΔUGN, and 3. ΔUJG

Whereby segment UN is perpendicular to segment JG, we have;

ΔUJN and ΔUGN are right triangles

∴ ∠UNJ = ∠UNG = 90° by definition of segment UN being perpendicular to segment JG

NU ≅ NU by reflexive property

Whereby UN bisects ∠JUG and segment JG, we have;

JN = GN by definition of a bisected segment

Therefore, we have;

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

7 0
3 years ago
The average of your first 6 tests is 82. If your test average after your seventh test is an 80.5, what did you score on the seve
mart [117]
So average is  of the first 6 tests is 82   well that means 

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying 

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6  = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute. 

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5 



7 0
3 years ago
Eight sided dice can be described as two square based pyramids stuck together at
kobusy [5.1K]
It costs $3.63 more for the gold die than the gold plated die.

The volume of each half of the die is given by the formula

V=1/3s³.

This means the total volume is V = 2(1/3s³) = 2(1/3(2³)) = 16/3 = 5.33 mm³.

For the solid gold die, we know that it weighs 0.02g per mm³:

5.33(0.02) = 0.1066g

Gold costs $40.38 per gram:
40.38(0.1066) = $4.30

For the plastic die, plastic weighs 0.01 g per mm³:
0.01(5.33) = 0.0533g

Plastic costs $10 per gram:
0.0533(10) = 0.533 ≈ $0.54.

We also need to find the surface area, as it will be painted.  Each face is an equilateral triangle; the area of a triangle is given by the formula

A = 1/2bh

We need to use the Pythagorean theorem to find the height.  The height will be one leg and 1/2 of the base will be the other; the slanted side will be the hypotenuse:

h² + (1/2(2))² = 2²
h² + 1² = 2²
h² + 1 = 4
h² = 3
h = √3

The area of the triangle would then be A = 1/2bh = 1/2(2)(√3) = √3.  There are 8 such faces on the die, so the total surface area would be 8√3 = 13.86mm².

Paint costs $0.01 per mm²:
13.86(0.01) = 0.1386 ≈ $0.14

Together the cost for the plastic is 0.14+0.53 = $0.67.

The difference between it and the cost for the gold die is 4.30 - 0.67 = $3.63.
5 0
3 years ago
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