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Ganezh [65]
3 years ago
7

Which element, if combined with chlorine, will have the greatest attraction for the chlorine electrons?

Chemistry
1 answer:
tatiyna3 years ago
8 0
As is correct my freind
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9474 millimeters to centimeters using scientific notation showing work
puteri [66]

Answer:

9.474 x 10^2

Explanation:

ok. first you have to get the value in the required unit so 9474mm/(10mm/cm) = 947.4 so scientific notation states that the number must be raised to any power of an integer and the value of the number being raised must be less than than 10 and more than or equal to 1

so it must have one digit in front so.. 947.4 becomes 9.474 and because you move 2 places to the left, ur power is positive 2

and proof 10^2 is 100 so multiply 9.474 by 100 and u will get 947.4 cm which is also 9474 mm

8 0
3 years ago
What is "Scarcity" <br><img src="https://tex.z-dn.net/?f=." id="TexFormula1" title="." alt="." align="absmiddle" class="latex-fo
Lana71 [14]

Explanation:

I don't know sorry ok I have some work so I m sorry

4 0
2 years ago
Read 2 more answers
Question 55 pm
Law Incorporation [45]

Answer:

They are magnetic lines and theses lines depict the invisible magnetic field around the magnet! Hope this helps I got it right on my quiz:)

Explanation:

3 0
3 years ago
Which statement is correct regarding the reaction below? 3A + 2B yields C + 2D The rate of formation of D is twice the rate of d
Vedmedyk [2.9K]

Answer:

The correct statements are:

The rate of disappearance of B is twice the rate of appearance of C.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

3A + 2B → C + 2D

Rate of the reaction:

R=-\frac{1}{3}\times \frac{d[A]}{dt}=-\frac{1}{2}\times \frac{d[B]}{dt}

-\frac{1}{3}\times \frac{d[A]}{dt}=\frac{1}{1}\times \frac{d[C]}{dt}

-\frac{1}{3}\times \frac{d[A]}{dt}=\frac{1}{2}\times \frac{d[D]}{dt}

The rate of disappearance of B is twice the rate of appearance of C.

\frac{1}{1}\times \frac{d[C]}{dt}=-\frac{1}{2}\times \frac{d[B]}{dt}

2\times \frac{1}{1}\times \frac{d[C]}{dt}=-\frac{1}{1}\times \frac{d[B]}{dt}

8 0
3 years ago
Read 2 more answers
when 32.4 g of water vapor condenses, how much heat is given off? The heat of vaporization for water is 40.67 kj/mol
egoroff_w [7]
When a water vapor condenses, heat is being released from the process. This heat is called latent heat of vaporization since the phase change happens without any change in the temperature. This value is constant per mole of a substance as a function of pressure and temperature. For this problem, we are given the heat of vaporization at a certain T and P. We use this value to calculate the total heat released from the process. We calculate as follows:

Total heat released: 32.4 g ( 1 mol / 18.02 g ) (40.67 kJ / mol) = 73.12 kJ

Therefore, 73.12 kJ of heat is released from the condensation of 32.4 g of water vapor.
3 0
3 years ago
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