<u>Answer:</u> The correct answer is Option D.
<u>Explanation:</u>
To calculate the hybridization of
, we use the equation:
![\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom (S) = 6
N = number of monovalent atoms bonded to central atom = 0
C = charge of cation = 0
A = charge of anion = 0
Putting values in above equation, we get:
![\text{Number of electron pair}=\frac{1}{2}[6]=3](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5B6%5D%3D3)
The number of electron pair around the central metal atom are 3. This means that the hybridization will be
and the electronic geometry of the molecule will be trigonal planar.
Hence, the correct answer is Option D.
Since the question is incomplete, the table has been searched in order to comply with the question.
Based on the table that I have provided, the order of increasing
depth from shallowest to deepest are the following; A,B,C,D,E. The reason that
this is the order to be chosen because the one responsible for making water
dense is the salt that is on the water and by that, the base is likely to sink
whereas the ones with less salt won’t be as thick compared those who have much
salt and will skim on its top.
<span>a large amount of energy is released when water dissociates into oppositely charged ions.</span>
I believe <span>Na2SO3 is the solution to the problem.</span>