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Arte-miy333 [17]
3 years ago
13

Which is a method that can be used to separate the components of a solution?

Chemistry
1 answer:
sashaice [31]3 years ago
4 0

Answer:

Distillation

Explanation:

i hope this helps

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Functional groups create active sites in molecules. The polar part of a molecule that can hydrogen bond to water is said be hydr
VMariaS [17]

Answer:

Polar/Hydrophilic

Explanation:

Fluorine, Nitrogen and Oxygen are strong electronegative atoms and by definition, Electronegativity is the amount of pull or the high affinity of an atom to electrons.

Polar bond occurs when there is a high difference between the electronegativity value of both atoms that take part in the bond.

A polar molecule has a net dipole from the distribution of its positive and negayive charges. Hydrophobic and Hydrophilic (in chemistry, Polar) are terms dependent on the overall distribution of charge in its molecule.

Therefore, bonds between C-N, C-O and C-Cl are polar covalent bonds a d this is because of the jigh electronegativity possessed by Nitrogen, Oxygen and Chlorine.

5 0
3 years ago
Calculate the number of moles of C2H6 (nC2H6) in 1.80×1023 molecules of C2H6.
dem82 [27]
1481.40 molecules of C2H6
6 0
3 years ago
The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane (C8H18) and calculate the mass (
Mariulka [41]

Answer:

3.09kg

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol

Mass of C8H18 from the balanced equation = 2 x 114 = 228g

Converting 228g of C8H18 to kg, we obtained:

228/1000 = 0.228kg

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 16 x 44 = 704g

Converting 704g of CO2 to kg, we obtained:

704/1000 = 0.704kg

From the equation,

0.228kg of C8H18 produced 0.704kg of CO2.

Therefore, 1kg of C8H18 will produce = 0.704/0.228 = 3.09kg of CO2

6 0
3 years ago
IUPAC NAME FOR<br><br> [Fe(H2O)6](NO3)3
Kaylis [27]

Answer:

hexaaquairon(III) trinitrate

7 0
1 year ago
2) If the density of chloroform is 1.48 g/mL, what is the volume of 541 g of chloroform?
Maurinko [17]

Answer:

V = 365.54 mL

Explanation:

Given that,

The density of chloroform, d = 1.48 g/mL

The mass of chloroform, m = 541 g

We need to find the volume of chloroform.

We know that,

Density = mass/volume

So,

V=\dfrac{m}{d}\\\\V=\dfrac{541\ g}{1.48\ g/mL}\\\\=365.54\ mL

So, the volume of chloroform is 365.54 mL.

5 0
3 years ago
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