Incomplete combustion<span> occurs when the supply of air or oxygen is poor. Water is still </span>produced<span>, but </span>carbon<span> monoxide and </span>carbon<span> are </span>produced<span> instead of </span>carbon dioxide<span>. The </span>carbon<span> is released as soot. </span>Carbon<span> monoxide is a poisonous gas, which is one reason why </span>complete combustion<span> is preferred to </span>incomplete combustion<span>.</span>
Answer:
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Explanation:
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Answer:
33 g.
Explanation:
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In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:
In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:
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Answer:
1.4 × 10^-4.
Explanation:
C3H6O3 + H2O <======> C3H5O3^- + H3O^+ ------------------------------------------(1).
So, from the question above we are given the following parameters or data which is going to help in solving this particular Question/problem;
=>concentration of the solution of lactic acid (CH3CH(OH)C00H) = 0.1 M and pH = 2.44.
Therefore, the concentration of the hydrogen ion[H^+} can be determined from the pH formula given below;
pH = - log { H^+}.
2.44 = - log { H^+}.
Therefore, {H^+} = 0.0036 M.
From the equation (1) given above, we have that the ratio for the equilibrium reaction is 1 : 1 : 1 :1. Therefore, molarity of C3H5O3^- = 0.0036 M and the molarity of C3H6O3 =( 0.1 - 0.0036 M) = 0.0964 M at equilibrium.
Hence, ka = {C3H5O3^-} { H3O^+} /{C3H6O3} = ( 0.0036 M)^2 /(0.0964 M) = 1.4 × 10^-4.
