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sveta [45]
3 years ago
12

How many molecules of CaCi2 are equivalent to 75.9 grams

Chemistry
1 answer:
horsena [70]3 years ago
8 0
<em>M CaCl₂: 40+(35,5×2) = 111 g/mol</em>


6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
X = (75,9×<span>6,02·10²³)/111
X = <u>4,116</u></span><span><u>·10²³</u> molecules of CaCl</span>₂

:)
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