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3 years ago

12

How many molecules of CaCi2 are equivalent to 75.9 grams

1 answer:

horsena [70]3 years ago

8 0

<em>M CaCl₂: 40+(35,5×2) = 111 g/mol</em>

6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
X = (75,9×<span>6,02·10²³)/111
X = <u>4,116</u></span><span><u>·10²³</u> molecules of CaCl</span>₂

:)

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