0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
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C = n/V
n = 0,35×0,175
n = 0,06125 mol
mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol
1 mol --------- 164g
0,06125 ---- X
X = 10,045g
To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.
Answer:
⇒ 
Explanation:
In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side
⇒ 
The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.
⇒ 
1. Mg + CuSO4 —> MgSO4 + Cu
=> Single displacement reaction
2. 2HCI + Mg(OH)2 —> MgCI2 + H2O
=> Acid - base reaction
3.AgNO3 + NaCI —> AgCI + NaNO3
=> Double displacement reaction
Answer: 1.99 mol h20
Explanation:
you have 36.030 g, trying to get it into mols
to get from g to mols, use the molar mass (periodic table)
36.030 g h20 (1 mol/18.02g) = 1.99 mol h20
The answer is sodium chloride.
Explanation:
Sodium chloride refers to table salt, and is the most abundant of salts found in seawater.