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Ratling [72]
3 years ago
8

Wht are the trends for electronegativity and ionzation energy similar​

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
3 0

Answer:

Along period electronegativity and ionization energy increases.

Along group electronegativity and ionization energy decreases.

Explanation:

Along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. Thus the attraction of the atoms for valance electrons increases. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required, and electronegativity also increases.

Along group:

As we move from top to bottom in periodic table the atomic sizes increases.The electrons are added in next energy level in every next element. Thus the valance electrons farther away from the nucleus and hold of nucleus becomes weaker,  because of weak nuclear attraction atomic radii increases and electronegativity and ionization energy decreases.

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Hope this helps :)

- jp524

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What causes atoms to share electrons equally with atoms, but unequally share with others?
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Answer:

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What should you do if your bunsen burner does not light after a few tries with the striker?
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A compound with the empirical formula CH 2 CH2 has a molar mass of 126 126 g/mol. What is the molecular formula for this compoun
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<u>Answer:</u> The molecular formula of the compound is C_9H_{18}

<u>Explanation:</u>

We are given:

Empirical formula of the compound = CH_2

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 126 g/mol

Mass of empirical formula = 12+(2\times 1)]=14g/mol

Putting values in above equation, we get:

n=\frac{126g/mol}{14g/mol}=9

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(9\times 1)}H_{(9\times 2)}=C_9H_{18}

Hence, the molecular formula of the compound is C_9H_{18}

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