Answer:
Explanation:
The rate of reaction will not depend upon concentration of reactant . It will be always constant and equal to .0089M s⁻¹.
Initial moles of reactant = 400 x 10⁻³ mole in 5 L
molarity = 400 x 10⁻³ /5 M
= 80 x 10⁻³ M .
= .08M
no of moles reacted in 2 s = .0089 x 2
= .0178 M
concentration left = .08 - .0178 M
= .0622 M .
No of moles left in 5 L
= 5 x .0622 = .31 moles .
A)Cu2O(s) + C(s) ———> 2Cu(s)+ CO(g)
B)H2(g) +Cl2(g)———> 2HCl(g)
The student stirs it because he wants the reaction to take place more quickly.
