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Lena [83]
2 years ago
7

An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d 13.53 g/cm3), what is its volum

e? (b) How much would the vial weigh if it were filled with water (d 0.997 g/cm3 at 25°C)?
Mathematics
1 answer:
Artist 52 [7]2 years ago
5 0
We can determine the mass of liquid mercury inside the vial by taking the diffrence between the filled vial and the empty vial. The weight of liquid mercury is 130.24 grams. The equivalent volume is obtained through the density. The volume is 9.626 cm3. If the substance inside is water, the volume is 130.632 grams
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A+44=B<br> A=1x+76<br> B=-6x+134 <br> What is the value of A?
Rashid [163]
Hi there! A = 78

A + 44 = B
We can plug in the values of A and B into the equation. We then get an equation with only one variable (x), which we can solve.

1x + 76 + 44 = - 6x + 134
Collect terms.

1x + 120 = - 6x + 134
Add 6x to both sides.

7x + 120 = 134
Subtract 120 from both sides

7x = 14
Divide both sides by 7

x = 14 / 7 = 2

A = 1x + 76
Now plug in the value of x we just found

A = 2 + 76 = 78
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