Ned has a sandbox that he wants to fill with 1 foot of sand. About how much sand will he need? (The measurements are for the ins
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Answer:
They charged <u>$6</u> for washing and <u>$2</u> for vacuuming the car.
Step-by-step explanation:
Let the charge of washing a car be 'x'.
And also let the charge of vacuuming a car be 'y'.
Now according to question, Trisha raised $38 washing 5 cars and vacuuming 4 cars.
So framing the above sentence in equation form, we get;
Again according to question, Byron raises $28 by washing 4 cars and vacuuming 2 cars.
So framing the above sentence in equation form, we get;
Now multiplying equation 2 by '2', we get;
Now we subtract equation 1 from equation 3 and get;
Now substituting the value of 'x' in equation 1, we get;
Hence They charged <u>$6</u> for washing and <u>$2</u> for vacuuming the car.
Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,