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denpristay [2]
3 years ago
11

Three 100 nCcharged objects are equally spaced on a straight line. The separation of each object from its neighbor is 0.3 m. Fin

d the force exerted on the center object if the rightmost charge is negative and the other two are positive.
Physics
1 answer:
Rainbow [258]3 years ago
6 0

Answer:

0N

Explanation:

Parameters given:

Q1 = Q2 = Q3 = 100 * 10^(-9) C

r = 0.3 m

The net force on the middle charge is:

F = F(1,2) + F(2,3)

Where F(1,2) = force due to Q1 on Q2

F(2,3) = force due to Q3 on Q2

F(1,2) = k*Q(1)*Q(2)/r²

F(1,2) = [9 * 10^9 * 100 * 10^(-9) * 100 * 10^(-9)]/(0.3²)

F(1,2) = 0.001N

F(2,3) = k*Q(2)*Q(3)/r²

F(2,3) = [9 * 10^9 * 100 * 10^(-9) * -100 * 10^(-9)]/(0.3²)

F(2,3) = -0.001N

Therefore,

F = 0.001 - 0.001

F = 0N

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