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andrey2020 [161]
3 years ago
13

The rate constant for the first-order decomposition of cyclobutane at 500 °C is 9.2 x 10−3 s−1. How long will it take (in second

s) for 80.0% of a sample of C4H8 to decompose?
Chemistry
1 answer:
kherson [118]3 years ago
6 0
Wiiwiwieicocowoodoxx
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What is the wavelength of spectral line resulted from the electron transition from n=3 to n=2 in a hydrogen atom.
MakcuM [25]

Answer:

\lambda=6.56x10^{-7}m

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m

Best regards!

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4 years ago
Calculate the percent of Cl in KClO4
sergejj [24]

Answer:

25.6 %.

Explanation:

  • To calculate the % of Cl in KClO₄:

<em>% Cl = [Atomic mass of (Cl)/molar mass of KClO₄] x 100</em> = [(35.5 g/mol)/(138.55 g/mol)] x 100 = <em>25.62 % ≅ 25.6 %.</em>

7 0
4 years ago
Which observation illustrates the law of conservation of mass?
const2013 [10]
The conservation of mass states that the total mass of reactants present before the reaction occurs is equal to the total mass of products after the reaction. From the choices, the second choice deems fit for the description of the law.
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3 years ago
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Which of the following is the chemical formula for Hydrogen Chloride?
anygoal [31]

Answer:

The answer is (b) HCl

Explanation:

6 0
3 years ago
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What is the density of nitrogen gas if 0.186 g occupies a volume of 110 mL?
Anvisha [2.4K]

Answer:

d=1.69\times 10^{-3}\ g/mL

Explanation:

Given that,

Mass, m = 0.186 g

Volume occupies, V = 110 mL

We need to find the density of Nitrogen gas. The mass per unit volume is called density of an object. It is given by the formula as follows :

d=\dfrac{m}{V}\\\\d=\dfrac{0.186\ g}{110\ mL}\\\\=1.69\times 10^{-3}\ g/mL

So, the required density is 1.69\times 10^{-3}\ g/mL.

4 0
3 years ago
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