option c...have the waves move thru the vacuum or space
Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :



v = 2 m/s
Hence, their speed after collision is 2 m/s.
It is a reflecting telescope and a compound microscope. I know this for sure
48 M to get the answer add the area of the triangle and rectangle under the line
homozygous dominant:(BB) got 2 of them
heterozgous dimonant: (Bb) got 2 of them
homozygous Recessive: (none)