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Ne4ueva [31]
3 years ago
9

Josh and Jake are both helping to build a brick wall which is 6 meters in height. They each lay 250 bricks, but Josh finishes th

is task in 3 hours while Jake requires 4.5 hours to complete his part. Who does more work, or do they both do the same amount? Who has more power? Explain.
Physics
1 answer:
Molodets [167]3 years ago
5 0
<span>Each laid 250 bricks but while Jake was still working, Josh was lounging in the shade. Josh has more power but that power was only on for 3 hours out of 4.5. Obviously Josh could get more done is less time as long as he keeps working. Jake will get the hang of it soon.</span>
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A basketball player standing under the hoop shoots the ball straight up with an initial velocity of v0Part (a) What is the maxim
Mama L [17]

Answer:

Maximum height will be h=\sqrt{\frac{v_0^2}{2g}}

Explanation:

We have given initial velocity through which basketball is thrown =v_0

Acceleration due to gravity =g\  m/sec^2

At maximum height velocity will be zero

So final velocity v = 0 m /sec

According to third equation of motion v^2=u^2+2gh

0^2=v_0^2-2gh ( Negative sign is due to upward acceleration )

h=\sqrt{\frac{v_0^2}{2g}}

6 0
3 years ago
Suppose you have two meter sticks, one made of steel and one made of invar (an alloy of iron and nickel), which are the same len
Mekhanik [1.2K]

Answer:

  • The difference in length for steel is 2.46 x 10⁻⁴ m
  • The difference in length for invar is 1.845 x 10⁻⁵ m

Explanation:

Given;

original length of steel, L₁ = 1.00 m

original length of invar, L₁ = 1.00 m

coefficients of volume expansion for steel, \gamma_{st.} =  3.6 × 10⁻⁵ /°C

coefficients of volume expansion for invar, \gamma_{in.} =  2.7 × 10⁻⁶ /°C

temperature rise in both meter stick, θ = 20.5°C

Difference in length, can be calculated as:

L₂ = L₁ (1 + αθ)

L₂  = L₁ + L₁αθ

L₂  - L₁ = L₁αθ

ΔL = L₁αθ

Where;

ΔL is difference in length

α is linear expansivity = \frac{\gamma}{3}

Difference in length, for steel at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{3.6*10^{-5}}{3} = 1.2*10^{-5} /^oC

ΔL  = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m

Difference in length, for invar at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{2.7*10^{-6}}{3} = 0.9*10^{-6}/^oC

ΔL  = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m

8 0
3 years ago
An ideal parallel - plate capacitor consists of two parallel plates of area A separated by a distance d. This capacitor is conne
Svetradugi [14.3K]

Answer:

The capacitance is cut in half.

Explanation:

The capacitance of a plate capacitor is directly proportional to the area A of the plates and inversely proportional to the distance between the plates d. So if the distance was doubled we should expect that the capacitance would be cut in half. That can be verified by the following equation that is used to compute the capacitance in such cases:

C = (\epsilon)*(A/d)

Where \epsilon is a constant that represents the characteristics for the insulator between the plates. A is the area of the plates and d is the distance between them. When we double d we have a new capacitance, given by:

C_new = (\epsilon)*(A/2d)

C_new = (1/2)*[(\epsilon)*(A/d)]

Since C = (\epsilon)*(A/d)] we have:

C_new = (1/2)*C

4 0
3 years ago
Solve the equation 3x^2+8x+5=0
Pachacha [2.7K]
3x^2+8x+5=0\\&#10;3x^2+3x+5x+5=0\\&#10;3x(x+1)+5(x+1)=0\\&#10;(3x+5)(x+1)=0\\&#10;x=-\dfrac{5}{3} \vee x=-1
4 0
3 years ago
How are base units and derived units related?
Vlad1618 [11]

Answer:

SI derived units

Other quantities, called derived quantities, are defined in terms of the seven base quantities via a system of quantity equations. The SI derived units for these derived quantities are obtained from these equations and the seven SI base units.

Explanation:

Hope this helps :D

8 0
3 years ago
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