Answer:
x_total = 20m
Explanation:
This is an exercise in kinematics, we will look for the distance it travels during the reaction time, where there is no braking, and then the distance during the deceleration.
Distance traveled during response time
v = x₁ / t
x₁ = v t
let's calculate
x₁ = 10 0.75
x₁ = 7.5 m
Now we calculate the distance during braking, the final speed is zero (v = 0)
v² = v₀² - 2 a x₂
x₂ = v₀² / 2 a
let's calculate
x₂ = 10² / (2 4)
x₂ = 12.5m
the total stopping distance is
x_total = x₁ + x₂
X_total = 7.5 + 12.5
x_total = 20m
Answer:
16m
Explanation:
Given parameters:
Time = 4s
Initial velocity = 0m/s
Acceleration = 2m/s²
Unknown:
How far will the body move = ?
Solution:
To solve this problem, we use the expression below:
s = ut + at²
s is the distance
u is the initial velocity
t is the time
a is the acceleration
s = (0 x 4) + ( x 2 x 4²) = 16m
Answer:
419815.72 N
Explanation:
F = Force
t = Time
Average speed
Time = Distance / Speed
Impulse
The force exerted on the pier is 419815.72 N
Answer:
You will find out that the turgor pressure will be greater at the leaf end
Explanation:
Comparing turgor pressure at two different ends of a sieve tube. With one end of the sieve tube located within a mature leaf, and the other end located within the roots. When comparing the turgor pressure within the sieve tube at these two locations, you discover that the turgor pressure will be greater at the leaf end.