Answer:
1.696 nm
Explanation:
For a diffraction grating, dsinθ = mλ where d = number of lines per metre of grating = 5510 lines per cm = 551000 lines per metre and λ = wavelength of light = 467 nm = 467 × 10⁻⁹ m. For a principal maximum, m = 1. So,
dsinθ = mλ = (1)λ = λ
dsinθ = λ
sinθ = λ/d.
Also tanθ = w/D where w = distance of center of screen to principal maximum and D = distance of grating to screen = 1.03 m
From trig ratios 1 + cot²θ = cosec²θ
1 + (1/tan²θ) = 1/(sin²θ)
substituting the values of sinθ and tanθ we have
1 + (D/w)² = (d/λ)²
(D/w)² = (d/λ)² - 1
(w/D)² = 1/[(d/λ)² - 1]
(w/D) = 1/√[(d/λ)² - 1]
w = D/√[(d/λ)² - 1] = 1.03 m/√[(551000/467 × 10⁻⁹ )² - 1] = 1.03 m/√[(1179.87 × 10⁹ )² - 1] = 1.03 m/1179.87 × 10⁹ = 0.000848 × 10⁻⁹ = 0.848 × 10⁻¹² m = 0.848 nm.
w is also the distance from the center to the other principal maximum on the other side.
So for both principal maxima to be on the screen, its minimum width must be 2w = 2 × 0.848 nm = 1.696 nm
So, the minimum width of the screen must be 1.696 nm
Potential energy is defined as
here we have
mg = weight = 5 N
now for different heights we can say
U = mgh
so potential energy in all three shells will be different and increases with height
Answer:
61.105 C
Explanation:
Charge: This can be defined as the product of current flowing through a circuit and time. The S.I unit of charge is coulomb's (C)
I = Q/t ................. Equation 1
Where I = current, Q = Charge, t = time.
Note: The current through a cross sectional area of the compressor is the amount of charge passing through the area per unit time.
Q = It ............... Equation 2
Given: I = 121 A, t = 0.505 A.
Substitute into equation 2
Q = 121(0.505)
Q = 61.105 C.
Hence the charge passing through the cross sectional area of the circuit = 61.105 C
The force of gravity starts to decrease since your traveling away from the atmosphere.
Chemical energy is transformed in your body