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saw5 [17]
3 years ago
13

Low sun angles result in reduced solar energy because:

Physics
1 answer:
Aleks04 [339]3 years ago
5 0
Solar energy is a form of renewable energy that is harnessed using the technology of the photovoltaic cells. These cells are composed of semiconductors. When the light from the sun hits the semiconductor, the energy from the light particles, or photons, cause the electrons in the semiconductor to be 'excited'. When the electron moves across the semiconductor platforms, the electron flows, thus creating electricity.

Therefore, as much as possible, you want to capture all of the sun's light. This can be achieved when the Sun is high up the sky. But if there is low sun angle, then the concentration of the sun's energy that strike the PV cells would be lesser. 
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Vertical columns on the periodic table are called
Ymorist [56]

Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure

5 0
4 years ago
You are a scientist and would like to know if anew fertilizer will help plants grow faster. What would the experimental group be
Gennadij [26K]

Answer:

The plants that get different amounts of the new fertilizer.

if my answer helps you than mark me as brainliest.

6 0
3 years ago
The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr
WARRIOR [948]
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
y_n= \frac{n \lambda D}{a} (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
\lambda is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem, 
D=37.0 cm=0.37 m
\lambda=530 nm=5.3 \cdot 10^{-7} m
while the distance between the first and the fifth minima is
y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m (2)

If we use the formula to rewrite y_5, y_1, eq.(2) becomes
\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m
Which we can solve to find a, the width of the slit:
a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}=  1.57 \cdot 10^{-3} m=1.57 mm

7 0
4 years ago
A battery of voltage V delivers power P to a resistor of resistance R connected to it. By what factor will the power delivered t
Anettt [7]

Answer:

Explanation:

Power P = V² / R

a ) The resistance is changed to 2.90R

Power will become 1 / 2.9 times .

b )The voltage of the battery is now 2.90V, but the resistance is R

P = (2.9V)² / R

= 8.41 x V² / R

So power becomes 8.41 times

c )The resistance is 2.90R and voltage is 2.90V

Power P = (2.9V)² / 2.9 R

= 2.9 V²/R

So power becomes 2.9 times

d ) The resistance is 2.90R and the voltage is V/2.90

Power P = ( V/2.90)² x 1 / 2.90R

1 / ( 2.9 )³ x V² / R

= 1 / 24.389 x V² / R

So power becomes  1 / 24.389 times .

4 0
3 years ago
What are the four most important characteristics of an electric circuit?
kozerog [31]

Answer:

an energy source (AC or DC), a conductor (wire), an electrical load (device), and at least one controller (switch).

Explanation:

mark as brainliest please

4 0
2 years ago
Read 2 more answers
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