Answer:
You invested $22,000 in two accounts paying 3% and 5% annual interest, respectively. If the total interest earned for the year was $980, how much was invested at each rate?
Step-by-step explanation:
let x=amt invested at 3% rate of interest.
22000-x=amt invested at 5% rate of interest.
.03x+.05(22000-x)=980
.03x+1100-.05x=980
.02x=120
x=6000
22000-x=16000
amt invested at 3% rate of interest=$6,000
amt invested at 5% rate of interest=$16,000
<h2><em><u>Hope iit help you mark as Brainlist</u></em></h2>
Answer:
(4,3)
Step-by-step explanation:
The correct answer is C. They are going down by 3.
We need to get the limits first. When y = 0
0 = 64x - 8x^2
x = 0 and x = 8
The volume is
V = ∫ y dx from 0 to 8
V = ∫ (64x - 8x^2) dx from 0 to 8
V = 32x^2 - 8x^3/3 from 0 to 8
V = 682.67<span />
