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valentina_108 [34]
3 years ago
11

Transfer payments are used to redistribute money to various segments of society. T/F

Physics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

true

Explanation:

you pay back what you owe for what youve purchased

jenyasd209 [6]3 years ago
4 0

welp i think the answer is true

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Drivers a and b travel west from boston. driver a leaves three hours earlier traveling at a constant speed of 68mph. driver b fo
Elza [17]

We can answer this using one of the equations of linear motion:

v = d / t

where:

v = velocity

d = distance

t = time

<span>In the problem, we are asked to find for the time in which Driver B will catch up to Driver A. Therefore,  find the time when dA = dB. Rearranging the equation and equation dA and dB will result in:</span>

<span>vA * tA = vB * tB  ---> 1</span>

It was given that:

vA = 68 mph

tA = tB + 3 (since person A was travelling 3 hours earlier)

vB = 85 mph

tB = unknown

Substituting into equation 1:

68 * (tB + 3) = 85 * tB

68 tB + 204 = 85 tB

tB = 12 hrs

Therefore driver B would catch up to driver A after 12 hrs.

 

 

<span> </span>

5 0
3 years ago
Comment l'azote entre dans l'atmosphère
Kruka [31]

Answer:

shark puppet

Explanation:

8 0
4 years ago
_ can be felt as heat
Volgvan
Your answer would be (d.) infrared rays. Hope this helps!

6 0
4 years ago
The driver of a car wishes to pass a truck that is traveling at a constant speed of 19.3 m/s . Initially, the car is also travel
miss Akunina [59]

Answer:

A)    t = 10.56 s, B)  x = 235 m, C) v = 25.2 m / s

Explanation:

A) We can solve this problem using kinematics expressions.

The distance traveled by the truck is

       x_c = v_c t

Distance traveled by the car.

The car must travel the distance that separates them from the truck x₀=25.0.   Return to the lane at x₁ = 26.5 m. the length of the truck x₂=20.7m and the length of the car x₃ = 2  4.5 = 9 m, therefore the total length traveled by the car is

          x_t = x₁ + x₂ + x₃

          x_t = 26.5 + 20.7 +9 = 56.2 m

the distance traveled by the car when it returns to the lane is

         x_c + x_t = x₀ + v₀ t + ½ a t²

when the car passes the car the distance traveled by the two vehicles is the same, we substitute

         v_c  t + x_t = x₀ + v₀ t + ½ a t²

         ½ a t² + t (v₀ -v_c) + (x₀ - x_t) = 0

we substitute the values

         ½ 0.560 t² + t (19.3 -19.3) + (25.0 - 56.2) =

         0.28 t² -31.2 = 0

         t = \sqrt{ \frac{31.2}{0.28} }

         t = 10.56 s

This is the time it takes for the car to pass the truck and back into the lane.

B) the distance traveled is

        x = v₀ t + ½ a t²

        x = 19.3 10.56 + ½ 0.560 10.56²

        x = 235 m

C) the final velocity is

         v = v₀ + a t

         v = 19.3 + 0.560 10.56

         v = 25.2 m / s

3 0
3 years ago
Would a 500 μF or 100 μF capacitor keep a light bulb on longer? Explain your reasoning
balandron [24]

Answer:

The 500 would be able to keep a light bulb on longer.

Explanation:

The 500 would be able to hold more charge than the 100 which means it can keep the light bulb lit for longer.

5 0
3 years ago
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