Answer:
A change has occurred in a nucleus
The horse's position on the ground at time <em>t</em> is
<em>x</em> = (20 m/s) <em>t</em>
The baboon's height from the ground at time <em>t</em> is
<em>y</em> = 3 m - 1/2 <em>g</em> <em>t</em>²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.
The baboon falls and lands on the horse, so that the two animals meet when the baboon's height is 2 m from the ground, which happens after
2 m = 3 m - 1/2 <em>g</em> <em>t</em>²
1/2 <em>g</em> <em>t</em>² = 1 m
<em>t</em>² = (2 m) / (9.80 m/s²)
<em>t</em> ≈ 0.452 s
In this time, the horse reaches the tree, so its distance from it is
(20 m/s) * (0.452 s) ≈ 9.04 m
Answer:
the frequency of a wave is equal to the linear speed divided the wavelength. so in equation form.
f = v / l
where f is the frequency
v iss the linear speed
l is the wavelength
f = ( 345 m/s ) / ( 4.38 mm ) ( 1 m / 1000 mm )
f = 78767 per second
Explanation:
hope it helps
Answer:
Velocity of the passenger = 78.8[km/h]
Explanation:
In order to solve this problem, we must observe the train from a distant point of the train. In this way we can observe that the train moves at 80[km/h] relative to the ground.
In such a way that the passenger moves in a direction contrary to the movement of the train.
![v_{pass}=80-1.2\\ v_{pass}=78.8[km/h]](https://tex.z-dn.net/?f=v_%7Bpass%7D%3D80-1.2%5C%5C%20v_%7Bpass%7D%3D78.8%5Bkm%2Fh%5D)
The Observer located outside the train will see how the passenger moves away at 78.8 [km / h] and not at 80[km/h] which is the speed of the train.
