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kkurt [141]
3 years ago
15

***FIRST CORRECT ANSWER GETS A BRAINLIEST***

Physics
2 answers:
dlinn [17]3 years ago
5 0
I think the answer is-D, it is halved. Hope I’ve helped ;)
melomori [17]3 years ago
3 0

Answer:

Explanation: It is halved

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The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
BigorU [14]

1. Frequency: 7.06\cdot 10^{14} Hz

The frequency of a light wave is given by:

f=\frac{c}{\lambda}

where

c=3\cdot 10^{-8} m/s is the speed of light

\lambda is the wavelength of the wave

In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


4 0
3 years ago
Read 2 more answers
If an element has 7 electrons how many of them will be in the 2nd energy level
inna [77]
Well first you can not go to the 2nd energy level without the first so the first takes up 2 electrons leaving you 5 electrons and the recommended amount is 8 electrons so you would have 5 electrons left
8 0
4 years ago
Read 2 more answers
What must be the distance (in meters) between a point charge q1 = 16 μC and a point charge q2 = 32 μC for the electrostatic forc
adoni [48]

Answer:

d = 0.71 meters

Explanation:

It is given that,

Charge 1, q_1=16\ \mu C=16\times 10^{-6}\ C

Charge 2, q_2=32\ \mu C=32\times 10^{-6}\ C

Electrostatic force between charges, F = 9 N

Let d is the distance between the charges. The electrostatic force between the charges is given by the product of charges and divided by square of distance between them. Mathematically, it is given by :

F=k\dfrac{q_1q_2}{d^2}

d=\sqrt{\dfrac{kq_1q_2}{F}}

d=\sqrt{\dfrac{9\times 10^9\times 16\times 10^{-6}\times 32\times 10^{-6}}{9}}

d = 0.71 meters

So, the distance between the charges is 0.71 meters. Hence, this is the required solution.

6 0
4 years ago
An electron is ejected from the cathode by a photon with an energy slightly greater than the work function of the cathode. How w
Ksivusya [100]

It will be approximately equal.

<h3>How will the final kinetic energy change?</h3>

We can infer that all of the energy in the electron is Potential energy (PE) because the energy provided by the photon is hardly enough to outweigh the work function.

It will gain kinetic energy (KE) as it advances in the direction of the anode because it is moving through an electric field. All of the PE will have been transformed to KE by the time it reaches the anode.

According to the question

K = hf - W

W = Work function

The energy of photons is comparable. After conversion, there was only a little amount of KE remaining.

Therefore, PE (W) essentially equals KE (K).

It will about be equal.

Learn more about work function here:

brainly.com/question/19595244

#SPJ4

3 0
2 years ago
A water balloon cannon is fired at 35 m/s at an angle of 50∘ above the horizontal. How far away will it fall?
hoa [83]
Use the equation in the physics reference sheet. You can use the distance formula
6 0
3 years ago
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