Circularity system........…….......
Answer:
I'm pretty sure it's the third one where velocity goes from positive to negative
Explanation:
the positive velocity is before the object hits the ground and the negative is after
Answer:
The speed of the car, v = 19.997 m/s
Explanation:
Given,
The centripetal acceleration of the car, a = 13.33 m/s²
The radius of the curve, r = 30 m
The centripetal force acting on the car is given by the formula
F = mv²/r
Where v²/r is the acceleration component of the force
a = v²/r
Substituting the values in the above equation
13.33 = v²/30
v² = 13.33 x 30
v² = 399.9
v = 19.997 m/s
Hence, the speed of the car, v = 19.997 m/s
Answer:
Both objects will undergo the same change in velocity
Explanation:
m = Mass of the Earth = 5.972 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Earth = 6371000 m
m = Mass of object
Any object which is falling has only the acceleration due to gravity.

The acceleration due to gravity on Earth is 9.81364 m/s²
So, the speeds of the objects will change at an equal rate of 9.81364 m/s² but the change will be negative when an object is thrown up.
Hence, both objects will undergo the same change in velocity.