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Sauron [17]
2 years ago
10

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at po

int A and lands in the water at point B, a horizontal distance L = 2.42 m from the base of the slide, determine the height h of the water slide.
Physics
1 answer:
irina [24]2 years ago
4 0

Answer:0.813 m

Explanation:

Given

height at which slide ends is h=1.8 m

Horizontal distance L=2.42 m moved by child from slide base to pool

At slide end Child has only horizontal velocity

horizontal velocity is given by u=\sqrt{2gH}

where H=height of slide

time taken by child to complete 1.8 m height

t=\sqrt{\frac{2h}{g}}

t=\sqrt{\frac{2\times 1.8}{9.8}}

t=0.606 s

Horizontal distance moved in this time

L=2.42=u\times t

2.42=\sqrt{2gH}\times 0.606

\sqrt{2gH}=3.99

H=0.813 m      

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Answer:

c.a_m

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6 0
3 years ago
A car drives 215 km east and then 45 km north. What is the magnitude of the car’s displacement? Round your answer to the nearest
34kurt

Displacement = (straight-line distance between the start point and end point) .

Since the road east is perpendicular to the road north,
the car drove two legs of a right triangle, and the magnitude
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8 0
3 years ago
Read 2 more answers
A tennis player hits a ball 2.0 m above the ground.
tangare [24]

Explanation:

initial height, yo = 2 m

initial velocity, u = 20 m/s

angle of projection,θ = 5 degree

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Use Second equation of motion for vertical motion

As it hits the ground in time t, so put y = 0

Taking positive sign, t = 0.84 s

The ball travels a horizontal distance x in time t

X = 20 Cos5 x t

X =  16.76 m

As this distance is more than the distance of net, so it clears the net.

Let t' be the time taken to travel a horizontal distance equal to the distance of net

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Let the vertical distance traveled by the ball in time t' is y'.

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It clears the net by a vertical distance of 2.008 - 1 = 1.008 m and horizontal distance 16.76 - 7 = 9.76 m

your welcome, and have a great day.

8 0
2 years ago
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