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Sauron [17]
2 years ago
10

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at po

int A and lands in the water at point B, a horizontal distance L = 2.42 m from the base of the slide, determine the height h of the water slide.
Physics
1 answer:
irina [24]2 years ago
4 0

Answer:0.813 m

Explanation:

Given

height at which slide ends is h=1.8 m

Horizontal distance L=2.42 m moved by child from slide base to pool

At slide end Child has only horizontal velocity

horizontal velocity is given by u=\sqrt{2gH}

where H=height of slide

time taken by child to complete 1.8 m height

t=\sqrt{\frac{2h}{g}}

t=\sqrt{\frac{2\times 1.8}{9.8}}

t=0.606 s

Horizontal distance moved in this time

L=2.42=u\times t

2.42=\sqrt{2gH}\times 0.606

\sqrt{2gH}=3.99

H=0.813 m      

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Answer:

1.7 m

Explanation:

v_x = Velocity of ball in x direction = 4.47 m/s

u_y = Velocity of ball in y direction = 0

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t = Time taken

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s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.7=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{0.7\times 2}{9.81}}\\\Rightarrow t=0.38\ \text{s}

Horizontal displacement is given by

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