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Sauron [17]
3 years ago
10

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at po

int A and lands in the water at point B, a horizontal distance L = 2.42 m from the base of the slide, determine the height h of the water slide.
Physics
1 answer:
irina [24]3 years ago
4 0

Answer:0.813 m

Explanation:

Given

height at which slide ends is h=1.8 m

Horizontal distance L=2.42 m moved by child from slide base to pool

At slide end Child has only horizontal velocity

horizontal velocity is given by u=\sqrt{2gH}

where H=height of slide

time taken by child to complete 1.8 m height

t=\sqrt{\frac{2h}{g}}

t=\sqrt{\frac{2\times 1.8}{9.8}}

t=0.606 s

Horizontal distance moved in this time

L=2.42=u\times t

2.42=\sqrt{2gH}\times 0.606

\sqrt{2gH}=3.99

H=0.813 m      

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7 0
3 years ago
PLEASE HELP
hichkok12 [17]

The correct answer is 195.6 N

Explanation:

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7 0
3 years ago
3. A model rocket takes 0.05 seconds to speed up from rest to its maximum velocity of 80 m/s.
nikklg [1K]

Answer:

1600 \frac{m}{s^2}

Explanation:

Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:

a = \frac{change-in-velocity}{time} = \frac{Vf-Vi}{t}

Where Vf is the final velocity of the object, (in our case 80 m/s)

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and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.

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