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jonny [76]
3 years ago
11

A ball of clay is moving at a speed of 12 m/s collides and sticks to a stationary ball of clay. If each ball has a mass of 13 kg

, what's the combined velocity of the two balls of clay after the collision
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

p_{f} = 6 m / s

Explanation:

We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved

Initial instant. Before the crash

        p₀ = m v +0

Final moment. Right after the crash

        p_{f} = (m + m) v_{f}

how the moment is preserved

        p₀ = p_{f}

       m v = 2 m v_{f}

       v_{f} = v / 2

we calculate

       v_{f} = 12/2

       p_{f} = 6 m / s

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5 0
3 years ago
A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

f_n=\frac{nv_s}{4L}

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L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

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8 0
3 years ago
what is the necessary condition within the hydrogen atom for balmer line photons to be absorbed by the hydrogen atom
luda_lava [24]

Explanation :

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If a photon gets absorbed, the electron will move to higher energy levels and then fall back to the lower energy levels. Then each time a photon will be absorbed whose energy is given by difference between the initial and final energy levels i.e

In Balmer series, the transition is from higher energy levels to n = 2.

So, the necessary condition for Balmer series is that the electron should be at first excited state or n = 2 level as shown in figure.


6 0
3 years ago
An antelope is being chased across the savannah by a hungry lion. The lion runs at a
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8 0
2 years ago
Read 2 more answers
The minimum frequency of light needed to eject electrons from a metal is called the threshold frequency, ???? 0 ν0 . Find the mi
Allisa [31]

Answer:

<h2>E = 2.8028*10⁻¹⁹ Joules</h2>

Explanation:

The minimum energy needed to eject electrons from a metal with a threshold frequency fo is expressed as E = hfo

h = planck's constant

fo = threshold frequency

Given the threshold frequency fo = 4.23×10¹⁴ s⁻¹

h = 6.626× 10⁻³⁴ m² kg / s

Substituting this value into the formula to get the energy E

E = 4.23×10¹⁴ *  6.626 × 10⁻³⁴

E = 28.028*10¹⁴⁻³⁴

E = 28.028*10⁻²⁰

E = 2.8028*10⁻¹⁹ Joules

7 0
3 years ago
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