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3 years ago

13

A block of mass 5 kg is descending with a constant velocity on an inclined plane at 30°. What is the value of the frictional for

ce?

1 answer:

sattari [20]3 years ago

4 0

Answer:28.9N

Explanation:

F=UR R=mg R=5×10 R=50N

U=tan© U=Tan30 U=1/√(3)

F=UR F=1/√(3) ×50

F=28.9N

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Answer:

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Explanation:

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Answer:

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