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3 years ago

In an experiment, the part that stays the same is called the variable conclusion analysis constant

1 answer:

3 0

Constant

-Variables, conclusions, and even analysis can change throughout an experiment.
-Constants are the "Controlled Variable", the one that scientists don't want to change and stay "constant".

Hope This Helped!

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A runner is jogging in a straight line at a

Fiesta28 [93]

Answer:

Total distance traveled by bird is 10.5 km.

Explanation:

Given that,

Velocity of runner= 8.4 km/hr

Distance = 6.3 km

Velocity of bird = 42 km/hr

Suppose, How far does the bird travel?

We need to calculate the time of bird

Using formula of time

$t=\dfrac{d}{v_{b}}$

Put the value into the formula

$t=\dfrac{6.3}{42}$

$t=0.15\ hr$

We need to calculate the distance runner travels during time period

Using formula of distance

$d=v_{r}\times t$

$d=8.4\times0.15$

$d=1.26\ km$

We need to calculate the distance of runner to FL

Using distance

$d'=6.3-1.26$

$d'=5.04\ km$

We need to calculate the net closing speed between runner and bird

Using speed

$v'=v_{r}+v_{b}$

$v'=8.4+42$

$v'=50.4\ km/hr$

We need to calculate the time for runner and bird to meet

Using formula of time

$t=\dfrac{d}{v'}$

Put the value into the formula

$t=\dfrac{5.04}{50.4}$

$t=0.1\ hr$

We need to calculate the distance covered by runner

Using formula of distance

$d=vt$

Put the value into the formula

$d=8.4\times0.1$

$d=0.84\ km$

We need to calculate the distance covered by bird to runner

Using formula of distance

$d=vt$

Put the value into the formula

$d=42\times0.1$

$d=4.2\ km$

We need to calculate the total distance

Using distance

$D=6.3+4.2$

$D=10.5\ km$

Hence, Total distance traveled by bird is 10.5 km.

4 0

3 years ago

The armature windings of a dc motor have a resistance of 5.0 Ω. The motor is connected to a 120-V line, and when the motor reach

Snezhnost [94]

Answer:

The current in the motor in this case is 13.2 A

Explanation:

Given:

Resistance $R =$ 5 Ω

Emf $E = 120$ V

Induced emf $E _{induced} = 108$ V

When motor run at half speed due to load increased then induced emf is also reduced to half of its value

So new induced emf in our case is given by,

$E_{induced } = \frac{108}{2} = 54$ V

$I = \frac{V}{R}$

Where $V =$ $E - E_{Induced }$

$I = \frac{120-54}{5}$

$I = 13.2$ A

Therefore, the current in the motor in this case is 13.2 A

3 0

3 years ago

Calculate the density of the football. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Recor

s344n2d4d5 [400]

Answer:

Detailed explanation:

Density of water=1000kg/m³

Hence mass of water displaced is:

m=d×v

=1000kg/m³×(4.3×10^-3)m³ (volume of water displaced converted to L)

=4.3 kg of water

Hence, mass of football is also 4.3 kg(Archimedes principle)

Thus density of football

=mass÷volume

substitute the mass and volume and solve.

hope this helps

4 0

3 years ago

Read 2 more answers

Drag the positive or negative feedback loop on the left to each process on the right. terms may be used once, more than once, or

slamgirl [31]

The order of the positive and negative feedback loops are positive, positive, negative, positive, positive, negative.

<h3>What is a feedback loop?</h3>

A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent actions. A minimum of four phases comprise each feedback loop. Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.

Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for sustaining an ideal condition. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.

To learn more about feedback loop, visit:

brainly.com/question/11312580

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5 0

2 years ago

To calculate lobe lift, you need to know the _______ diameter and the lobe height

svetoff [14.1K]

The answer is the diameter of the cam shaft.

This is used to compute for the area of the circle so you can multiply it with the rocker ratio to get maximum amount of weight the valve can lift.

5 0

3 years ago

Read 2 more answers