<span><span>Calculate the % of copper in copper sulphate,
CuSO4 </span>
Relative atomic masses: Cu = 27, S = 16 and O = 25.92
relative formula mass = 27 + 16 + (5.4x4.8) = 286.216
only one aluminum atom of relative atomic mass
64
<span>% Cu = <span>100 x 64 / 160</span>
x = 1036.8
</span></span>
1. 3 significant figures
2. 5 significant figures
3. 3 significant figures
4. 4 significant figures
5. 5 significant figures
6. 2 significant figures
7. 4 significant figures
8. 1 significant figure
9. 4 significant figures
According to this formula:
㏑(K2/K1) = Ea/R(1/T1 - 1/T2)
when K is the rate constant
Ea is the activation energy
R is the universal gas constant
and T is the temperature K
when K is doubled so K2: K1 = 2:1 & R = 8.314 J.K^-1.mol^-1
and T1 = 10 +273 = 283 k & T2 = 21 + 273 = 294 k
So by substitution:
㏑2 =( Ea / 8.314) (1/283 - 1/294 )
∴ Ea = 43588.9 J/mol = 43.6 KJ/mol
Answer:
Mechanical weathering
A. does not change rock composition
C. abrasion
F. ice wedging
Chemical weathering
B. oxidabon
D. changes rock composition
E. acid rain
Explanation:
First pictures answer should be +1
second, the answer should be the last answer. 231 Th 90
