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3 years ago

13.0 g NaHSO4 is dissolved in water to make a 2.00 L solution what is the molarité

Chemistry

1 answer:

Sati [7]3 years ago

8 0

Answer:

0.054 M

Explanation:

1 mol NaHSO4 -> 120 g

x ->13 g

x= 0.108 mol NaHSO4

M= mol solute/ L solution

M= 0.108 mol NaHSO4/ 2.00L

M= 0.054 M

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Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

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Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of $H_2$ gas and 1 mole of $Br_2$ liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

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The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

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An 80 kg long jumper in flight accelerates at a rate of 10 m/s^2. What is the force of the long jumper

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