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VladimirAG [237]
3 years ago
7

What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?

Chemistry
1 answer:
Law Incorporation [45]3 years ago
5 0
The answer is 0.975 L

Volume = mol/Molarity

We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:

Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol

So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles

Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L
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The conversion factor of joule to kilocalories is 
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What is the atomic number of an atom that has fie neutrons and four electrons
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Which of the following sign does not indicate that a chemical change has happened .
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Answer:

A.)

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Think of it this way: <em>internal changes within the product: chemical. External changes within the product: physical.</em>

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Identify the neutral element represented by this excited-state electron configuration, then write the ground-state electron conf
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Explanation:

Excited state configuration: 1s² 2s² 2p² 3s¹

Unknown:

Ground state configuration = ?

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Solution:

Let us start by understanding what a ground state configuration entails:

A ground state configuration shows the lowest allowed energy levels of an atom. The excited state denotes when electrons have moved to higher energy levels away from their ground state.

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In writing the electronic configuration of an atom, certain rules must be complied with.

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To fill the s-orbital = 2 electrons

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