Answer:
Moles of magnesium chloride can be produced are 0.2 moles
Explanation:
The reaction of Mg with Cl2 is:
Mg + Cl₂ → MgCl₂
<em>Where 1 mole of Mg reacts per mole of Cl₂ to produce MgCl₂.</em>
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As the reaction is 1:1, we need to convert the mass of both Mg and Cl₂ to moles. The lower number of moles will determine the moles of MgCl₂ that will be produced:
<em>Moles Mg -Molar mass: 24.3g/mol-:</em>
4.86g * (1mol / 24.3g) = 0.2 moles Mg
<em>Moles Cl₂ -Molar mass: 24.3g/mol-:</em>
21.27g * (1mol / 70.9g) = 0.3 moles Cl₂
As moles of Mg < moles of Cl₂, Mg is limiting reactant and moles of magnesium chloride can be produced are 0.2 moles
The correct answer is A. Brainliest would be much appreciated.
It should be the answer b but I’m not to sure
Answer:
Explanation:
a) The mass of the reactants is 2.36 grams, and the mass of the products is 1.57 grams plus the mass of the carbonic acid. Thus, using the law of conservation of mass, we get the mass of the carbonic acid is 2.36 - 1.57 = 0.79 grams.
b) The gram-formula mass of sodium bicarbonate is 84.006 g/mol, meaning that 2.36/84.006 = 0.028 moles were consumed. Thus, this means that in theory, 0.014 moles of carbonic acid should have been produced, which would have a mass of (0.014)(62.024)=0.868 grams. Thus, the percentage yield is (0.79)/(0.868) * 100 = 91%
