Total Earned Saturday: $45
Total Earned Sunday: $63
Total: $108
Time and a quarter means that you divide his normal rate by 4 and add that to his normal rate.
9/4 = 2.25 2.25 + 9 = 11.25
Jarvis makes $11.25 an hour on Saturdays.
Since he worked 4 hours, you multiply,
11.25 x 4 = 45.
<h3>What is the normal rate?</h3>
Time and three quarters mean that you multiply his normal rate by 3/4 and add that to his normal rate
9x0.75 = 6.75 6.75 + 9 = 15.75
Jarvis makes $15.75 an hour on Sundays. Since he worked 4 hours, you multiply 15.75 x 4 = 63.
To get the total, you add his earnings on Saturday and earnings on Sunday
45 + 63 = 108.
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Answer:
verdical lines have an undefined slope so it might be 4
Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Answer:
45 = 45
or
just 45.
Step-by-step explanation:
a = 6 , b = 2
3(6) + 4(2)^3 - 5 = 3(6) + 4(2)^3 - 5 (Given)
18 + 32 - 5 = 18 + 32 - 5 (Solve parenthesis)
45 = 45 (combine like terms)
45 does equal 45 so there is the solution. There is infinite many solutions.
Answer:
y + 4x - 6 = 0
Step-by-step explanation:
Rearranging the given equation:-
4y = x + 24
y = 1/4 x + 6
This has a y intercept of (0, 6) and a slope of 1/4.
Thus, the other line has a slope of -4 and passes through the point (0,6) also.
Using the Point-slope form of a straight line:-
y - y1 = m(x - x1)
y - 6 = -4(x - 0)
y + 4x - 6 = 0 is the required equation
