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Salsk061 [2.6K]
3 years ago
6

A balloon is inflated such that a radius is 7 cm what is the volume of air inside the balloon in milliliters

Chemistry
1 answer:
DedPeter [7]3 years ago
3 0

Answer:

V=14373.33\ \text{mm}^3

Explanation:

It is given that,

The radius of the inflated balloon is 7 cm.

We need to find the volume of air inside the balloon in milliliters.

The balloon is in the shape of a sphere whose volume is given by :

V=\dfrac{4}{3}\pi r^3\\\\\text{Put r = 7 cm}\\\\V=\dfrac{4}{3}\times \dfrac{22}{7}\times 7\times 7\times 7\\\\V=1437.33\ \text{cm}^3\\\\\text{We know that, 1 cm = 10 mm}\\\\\text{So},\\\\V=14373.33\ \text{mm}^3

Hence, the volume of the air inside the balloon is 14373.33\ \text{mm}^3.

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Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is LiOH.

We are given:

n_1=1\\M_1=0.10mol/L\\V_1=?mL\\n_2=1\\M_2=0.15mol/L\\V_2=10mL

Putting values in above equation, we get:

1\times 0.10\times V_1=1\times 0.15\times 10\\\\V_1=15mL

Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

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