1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisabon 2012 [21]
3 years ago
6

True or false A(n) rift valley forms where plates diverge on land.

Chemistry
2 answers:
motikmotik3 years ago
4 0

Answer:

True

Explanation:

vlabodo [156]3 years ago
3 0

Answer:

true

Explanation:

You might be interested in
HELP PLS (CHEMISTRY)
IRINA_888 [86]

The first most obvious thing to note is when naming transitional metals, you have to state its charge with roman numerals (except for 1 if I remember correctly). For example, Iron (lll), iron has a charge of 3.

4 0
2 years ago
When PCl5 solidifies it forms PCl4+ cations and PCl6– anions. According to valence bond theory, what hybrid orbitals are used by
Vlad1618 [11]

Answer:

sp³

Explanation:

Number of hybrid orbitals = ( V + S - C + A ) / 2

Where

H is the number of hybrid orbitals

V is the valence electrons of the central atom = 5

S is the number of single valency atoms = 4

C is the number of cations = 1

A is the number of anions = 0

For PCl₄⁺

Applying the values, we get:

H = ( 5+4-1+0) / 2

= 4

<u>This corresponds to sp³ hybridization.</u>

5 0
3 years ago
Read 2 more answers
How many grams of CO2 evolved from a 1.205g sample that is 36% MgCO3 and 44% K2CO3 by mass?
emmasim [6.3K]

Mass of CO₂ evolved : 0.108 g

<h3>Further explanation</h3>

Given

1.205g sample, 36% MgCO3 and 44% K2CO3

Required

mass of CO2

Solution

  • mass of MgCO₃ :

0.36 x 1.205 g=0.4338 g

mass C in MgCO₃(MW MgCO₃=84 g/mol,  Ar C = 12/gmol)

= (12/84) x 0.4338

= 0.062 g

  • mass of K₂CO₃ :

0.44 x 1.205 g = 0.5302 g

Mass C in K₂CO₃(MW=138 g/mol) :

= (12/138) x 0.5302

= 0.046 g

Total mass Of CO₂ :

= 0.062 + 0.046

= 0.108 g

7 0
3 years ago
Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent b
mojhsa [17]

Answer:

The answer to your question is: CO2

Explanation:

The information given is correct, Covalent bonds occur when atoms share one or more pairs of electrons, but also, covalent bonds occur with nonmetals, then,

a.NaCl     This elements form an ionic bond, so this option is incorrect.

b.Cl2      Here there are two non metals  but the form one single covalent bond, so this option is incorrect.

c.CO2  Carbon dioxide forms 2 double covalent bonds.

d.NH3 ammonium only forms single covalent bonds

6 0
3 years ago
Why is it called alkaline battery?
Delicious77 [7]
Alkaline battery are a type of primary battery dependent upon the reaction between zinc metal and manganese dioxide.
The alkaline battery gets its name because it has an alkaline electrolyte of potassium hydroxide, instead of the acidic ammonium chloride or zinc chloride electrolyte of the zinc-carbon batteries.
5 0
3 years ago
Other questions:
  • Give reason why wood is solid?
    6·2 answers
  • . A sample of crude oil has a density of 0.87 g/mL. What volume (in liters) does a 3.6 kg sample of this oil occupy
    5·1 answer
  • Which of the following will react violently with water to form a base?
    11·1 answer
  • A spherical balloon initially contains 25m3 of helium gas at 20o C and 150 kPa. A valve is now opened and the helium is allowed
    13·1 answer
  • Which particles can be stopped by human skin? ) alpha and beta particles only alpha particles alpha and gamma particles beta and
    15·2 answers
  • How many grams of hydrogen gas would be needed to form 8.0 grams of water
    6·1 answer
  • Wich symbols represent SI units for temperature?
    9·2 answers
  • How many moles of sand (SiO2) are in 30 g of sand?
    14·2 answers
  • Ammonia is produced by the Haber process. The equation is shown.
    8·2 answers
  • What is mole ? and it's unit​
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!