Question

A liquid has a density that varies with depth h, such that ρ=(0.001h+1.60)slug/ft3, where h is in feet.

Answer 1

We need to find pressure when h = 85 ft

We know the formula for pressure P = hρg, where h is the height of liquid, ρ is the density of liquid and g is the acceleration due to gravity value.

We have ρ = (0.001h+1.60)slug/$ft^3$ = 515.24 kg/$m^3$

                h = 25.908 m

                g = 9.8m/$s^2$

  So pressure, P = 25.908*515.24*9.8 = 13088.61 N/$m^2$

                             = 18.97 psi