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3 years ago

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A liquid has a density that varies with depth h, such that ρ=(0.001h+1.60)slug/ft3, where h is in feet.

1 answer:

Valentin [98]3 years ago

5 0

We need to find pressure when h = 85 ft

We know the formula for pressure P = hρg, where h is the height of liquid, ρ is the density of liquid and g is the acceleration due to gravity value.

We have ρ = (0.001h+1.60)slug/ $ft^3$ = 515.24 kg/ $m^3$

h = 25.908 m

g = 9.8m/ $s^2$

So pressure, P = 25.908*515.24*9.8 = 13088.61 N/ $m^2$

= 18.97 psi

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The work done by an engine equals one-fourth the energy it absorbs from a reservoir. True or False

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True IF the engine is 25% efficient. False otherwise.

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3 years ago

What is the value of the composite constant (Gme,/r2e) to be multiplied by the mass of the object mo, in equation below:

Sedbober [7]

To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.

The equation for the gravitational force between the Earth and the object on the surface of the Earth is

$F_g = \frac{Gm_em_o}{r^2_e}$

Where,

G = Universal gravitational constant

$m_e$ = Mass of Earth

$r_e$ = Distance between object and center of earth

$m_o$ = Mass of Object

The equation for the gravitational pulling force on the object due to gravitational acceleration is

$F_g = m_o g$

Equation the two expression we have

$m_o g = \frac{Gm_em_o}{r_e^2}$

$g = \frac{Gm_e}{r_e^2}$

This the acceleration due to gravity which is composite constant.

Replacing with our values we have then

$g = \frac{(6.67*10^{-11}N\cdot m^2/kg^2)(5.98*10^{24}kg)}{6378km(\frac{10^3m}{1km})^2}$

$g = 9.8m/s^2$

The value of composite constant is $9.8m/s^2$ . Here, the composite constant is nothing but the acceleration due to gravity which is constant always.

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3 years ago

A student redid the experiment of mixing room temperature water and warm

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Answer:

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3 years ago

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The root-mean-square value of an alternating current of S0Hz frequency is 10 ampere. The time taken by the alternating current i

stealth61 [152]

Answer:

(D ) $5\times10^{-3} sec$ and $14.14 amp.$

Explanation:

Given that, the rms value of current is 10 ampere and its frequency is 50 Hz.

Now maximum value of current can be calculated as,

$I_{max}=\sqrt{2}I_{rms}\\I_{max}=10\times \sqrt{2} \\I_{max}=14.14 amp.$

The time period is defined as,

$T=\frac{1}{f}\\ T=\frac{1}{50}\\ T=0.02 sec$

Now the time taken by alternating current going from zero to maximum value is,

$t=\frac{T}{4}\\ t=\frac{0.02}{4}\\ t=5\times 10^{-3}sec$

Therefore, the time taken by alternating current to reach maximum value is $t=5\times 10^{-3}sec$ and the peak value of current is $14.14 amp.$ .

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3 years ago

What force gives a 1.0 kg mass an acceleration of 7.0 m/s^2?

TiliK225 [7]

For this case we have that according to Newton's second law it is true that:

$F = m * a$

Where:

F: It is the force

m: It is the mass

a: It is the acceleration

According to the data we have:

$m = 1.0 \ kg\\a = 7.0 \frac {m} {s ^ 2}$

So, we have:

$F = 1.0 \ kg * 7.0 \frac {m} {s ^ 2}\\F = 7 \ N$

Thus, the applied force will be 7 Newtons.

Answer:

$F = 7 \ N$

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3 years ago

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