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3 years ago

1) Differences between Magnetic Induction and Demagnetization

Physics

1 answer:

Hatshy [7]3 years ago

6 0

Magnetic Induction is the process by which an object is magnetized by an external magnetic field.

Demagnetization is the process of removing magnetism from an object.

Explanation:

Magnetism is the property of a material to exert a notice magnetic force on anything that is electrically or magnetically charged. Ferromagnetic substances like iron can be magnetized permanently by putting them in an external magnetic field. These materials retain their magnetic properties up to a certain temperature, called the Curie point.

Demagnetization is the process of decreasing the magnetic properties of ferromagnetic materials by heating it past the Curie point, applying a strong magnetic field, applying alternating current, or hammering the metal. Demagnetization occurs naturally over time.

Keywords: magnetism, magnetic induction, demagnetization, Curie point, ferromagnetic.

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A freely suspended magnet always show north-south direction because Earth also shows magnetism.

Explanation:

Earth's magnetic field is similar to that of a bar magnet so it also have two poles; the south pole and the north pole. So when a bar magnet is freely suspended, it arranges itself in such a way that its north pole points towards the south pole of Earth and its south pole points towards the north pole of Earth. Because opposite poles attracts each other.

The south pole of earth's magnet is in geographical north because it attracts the north pole of suspended magnet . Similarly , the north pole of earth's magnet is in geographical south because it attracts the south pole of the suspended magnet . Hence, the suspended bar magnet shows north-south direction.

Keywords: north pole, south pole, magnet, Earth, bar magnet.

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A magnet has stronger force of attraction at the poles than in the middle because the magnetic field lines of a bar magnet are closer at the poles while they almost vanish in the middle comparatively.

Explanation:

Magnetic field lines are used to represent the magnetic field around a magnet. Magnetic field lines are continuous, forming closed loops without beginning or end. They go from the north pole to the south pole. The direction of the magnetic force is tangent to the magnetic field line at that point.

The strength of the magnetic force is directly proportional to the density of the magnetic field lines. Hence, the magnetic force is stronger near the poles and weakens in the middle.

Keywords: magnetic field lines, poles, magnetic force.

Learn more about magnetic field from brainly.com/question/1124815

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eduard

Answer:4A

Explanation:

Given

Mass is displace x= A units from its mean position x=0'

When it is set to free it will oscillate about its mean position with maximum amplitude A i.e. from x=-A to x=A

One cycle is completed when block returns to its original position

so first block will go equilibrium position x=0 and then to x=-A

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3 years ago

How would you produce electricity using a magnet

Sloan [31]

Answer:

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Explanation:

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2 years ago

A 20 kg object is dropped from a very tall building. What is the weight of this objects? After 5 seconds, how has the object fal

prohojiy [21]

1. What is the weight of this objects?

Weight is simply the product of mass and gravitational acceleration. Therefore the weight is:

w = 20 kg * 9.81 m/s^2

w = 196.2 kg m/s^2 = 196.2 N

2. After 5 seconds, how has the object fallen and what is its speed at this instant?

We can use the formula:

v = v0 + g t

where v0 = 0 since the object starts from rest, y is the distance it fell, t is time

y = 0 + 0.5 * 9.81 * 5^2 = 122.625 m

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3 years ago

An object is placed 10 cm in front of a diverging mirror. What is the focal length of the mirror if the image appears 2 cm behin

Dafna1 [17]

Answer:

the focal length of the mirror is : $f=-2.5\,\,cm$

Explanation:

Use the formula for the formation of image using a divergent mirror and recalling that the image (s') that this mirror formed is virtual, so it is entered as a negative number in the formula. Use the object position (s) as 10, the image position (s') as -2, and derive the value of the focal length:

$\frac{1}{s} +\frac{1}{s'}=\frac{1}{f}\\\frac{1}{10} +\frac{1}{-2}=\frac{1}{f}\\\frac{1}{10} -\frac{1}{2}=\frac{1}{f}\\\frac{10\,f}{10} -\frac{10\,f}{2}=\frac{10\,f}{f}\\f-5\,f=10\\-4\,f=10\\f=-2.5\,\,cm$

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3 years ago

A proton moves perpendicularly to a uniform magnetic field b with a speed of 3.7 × 107 m/s and experiences an acceleration of 5

svlad2 [7]

The magnetic force experienced by the proton is given by
$F=qvB \sin \theta$
where q is the proton charge, v its velocity, B the magnitude of the magnetic field and $\theta$ the angle between the direction of v and B. Since the proton moves perpendicularly to the magnetic field, this angle is 90 degrees, so $\sin \theta=1$ and we can ignore it in the formula.

For Netwon's second law, the force is also equal to the proton mass times its acceleration:
$F=ma$

So we have
$ma=qvB$
from which we can find the magnitude of the field:
$B= \frac{ma}{qv}= \frac{(1.67 \cdot 10^{-27}kg)(5\cdot 10^{13}m/s^2)}{(1-6 \cdot 10^{-19}C)(3.7 \cdot 10^7 m/s)}=0.014 T$

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2 years ago