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Ludmilka [50]
3 years ago
11

Graph the solution to the inequality 2x-3y<18

Mathematics
1 answer:
frutty [35]3 years ago
6 0

<, > - dotted line

≤, ≥ - solid line

2x-3y\dfrac{2}{3}x-6\\\\y=\dfrac{2}{3}x-6-\text{It's a linear function}\\\\for\ x=0\to y=\dfrac{2}{3}(0)-6=0-6=-6\to(0;\ -6)\\\\for\ x=6\to y=\dfrac{2}{3}(6)-6=2(2)-6=4-6=-2\to(6;\ -2)

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URGENT PLEASE HELP
Inga [223]

Answer:

y = - \frac{1}{3} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - \frac{1}{3} x + 2 ← equation of perpendicular line

4 0
3 years ago
How do you simplify that question? For algebra 1.
motikmotik
\left( \sqrt{x^{-3}} \right)^5 =  \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }


<span>Explanation for the last step:</span>
\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}

7 0
3 years ago
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STALIN [3.7K]
Hope this helps! As long as you keep posting I’ll keep answering- always happy to help!

7 0
3 years ago
Read 2 more answers
Write the equation of the line in slope-intercept form that has a slope of -5/2 and passes through the point (14,-39)
bonufazy [111]

Answer:

Step-by-step explanation:

The equation of the line in point-slope form;

y+39 = (-5/2)(x-14)

Rearrange to solve for y:

y+39 = (-5/2)x + 35

y = (-5/2)x + 4

4 0
3 years ago
A circular garden is surrounded by a circular path of 7m width.If the area of path is 770m²,find the area of the garden without
Serjik [45]

Answer:

Answer:

Radius of the circular garden

= 210 sq

=105m

Radius of the region covering the garden and the path =105m+7m

=112m

Area of the region between two concentric circles

with radius of outer circle R, and inner circle r =π(R sq−r sq)

Hence, the area of the path

=π(112sq−105 sq)= 7/22

(12544−11025)

= 33418/7

=4774m sq

HOPE THIS WILL HELP YOU MATE

8 0
3 years ago
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