Harold would be equally happy with receiving $95 today or $100 one year from today. Harold's friend Maud would bejust as happy r
2 answers:
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Answer:
5375
Explanation:
Given that:
Initial Fixed assets costing = $962000
Annual fixed costs = $403400
Variable cost per unit = $123.60
Sales price per unit = $249.00
Discount rate = 14%
Tax rate = 21%
The contribution per unit = Sales price - Variable cost
= $(249.00 - 123.60)
= $125.40
The present value break-even point(BEP) is the region of sales level where the net present value (NPV) equals zero.
Assuming that the sales level = p
i.e.
NPV = PV(of inflows - of outflows)
Inflows = (p * contribution per unit - annual fixed cost)( 1- tax rate) + depreciation * tax rate
= (p * 125.4 - 403400) ( 1 - 0.21) + depreciation * tax rate
where;
depreciation = initial fixed assest cost/ lifetime of the project
= (125.4p - 403400)*0.79 + (962000/6)*0.21
= (125.4p - 403400)*0.79 + (160333.33)*0.21
= (125.4p - 403400)*0.79 + 33670
Now, the PV of the inflows =PV factor(6 years, 14%) * inflows
Replacing the value for inflows, we have:
The PV of the outflows = Initial Fixed asset cost = $962000
∴
Equating both together using:
PV(of inflows - of outflows) = 0
((125.4p - 403400)*0.79 + 33670)* 3.8887 - 962000 = 0
((125.4p - 403400)*0.79 + 33670)* 3.8887 = 962000
(99.066p - 318686 + 33670) * 3.8887 = 962000
(99.066p - 285016) * 3.8887 = 962000
385.24p - 1108341.72 = 962000
385.24p= 962000 + 1108341.72
385.24p= 2070341.72
p = 2070341.72 / 385.24
p ≅ 5375
Answer:
And we can solve for y and we got:
And using condition (1) we can solve for x and we got:
So then the minimum cost for this case would be:
Explanation:
For this case the graph attached illustrate the problem for this case
We know that the total area is 60000, so then we have:
If we solve for x we got:
(1)
Now we can define the cost function like this:
We can use the condition (1) and if we replace in the cost function we have:
Since we need to minimize the cost, we can derivate the function in terms of y and we got:
And we can solve for y and we got:
And using condition (1) we can solve for x and we got:
So then the minimum cost for this case would be:
