Answer:
78.5 mL
Explanation:
Step 1: Given data
Mass of the lead fishing weight: 39.7 g
Volume of water in the graduated cylinder: 75.0 mL
Step 2: Calculate the volume of the lead fishing weight
The density of lead is 11.34 g/mL.
39.7 g × (1 mL/11.34 g) = 3.50 mL
Step 3: Calculate to what volume will increase the water level
The final volume of water will be equal to its initial value plus the volume displaced by the lead fishing weight.
V = 75.0 mL + 3.50 mL = 78.5 mL
