1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gregori [183]
3 years ago
8

hydrogen-2 is also known as deuterium as well as hydrogen-3 is known as tritium hydrogen-1 is our common hydrogen isotope a samp

le hydrogen gas has 99% hydrogen -1 ,0.8% deuterium , and 0.2% tritium what is the average atomic mass of this mixture of isotope to the thousands place
Chemistry
1 answer:
UkoKoshka [18]3 years ago
6 0
H-1 only has 1 proton and 1 electron, so its mass number is 1.
H-2 has one more neutron so its mass number is 2
H-3 has one more neutron than H-2 so its mass number will be 3.
average atomic mass = 1 x 99% + 2 x 0.8% + 3 x 0.2%
=1.012
You might be interested in
Which of the following reactant pairs will not react together to produce a reaction?
Art [367]
I think the correct answer from the choices listed above is option D. the substances cobalt and barium chloride will not react since cobalt os less active than barium so it does not have enough energy to displace barium in the compound. Hope this answers the question.
5 0
4 years ago
Por favor, necesito ayuda, es urgente!!!
PilotLPTM [1.2K]

Answer:

what type of language this is ??

4 0
3 years ago
Which of the following SI or metric units is a base unit?
Olin [163]
3. Ampere is the base unit for electric current.
8 0
3 years ago
How many grams of oxygen are required to react with 12.0 grams of octane(C8H18) in the combustion of octane in gasoline?
solniwko [45]

Answer : 42 grams of oxygen are required.

Explanation :

Step 1 : Write balanced chemical equation.

The combustion reaction of octane with oxygen can be written as,

2 C_{8}H{18} (g)  + 25  O_{2} (g) \rightarrow 16 CO_{2} (g) +18  H_{2}O (g)

Step 2 : Find moles of octane.

The given mass of octane is 12 g

Molar mass of octane is 114.2 g/mol

The moles of octane are calculated as,

moles =\frac{grams}{MolarMass}  =\frac{12g}{114.2g/mol}  = 0.105 mol

We have 0.105 mol octane.

Step 3: Use mole ratio from balanced equation to find moles of O₂

The mole ratio of octane and O₂ is 2 : 25. Let us use this as a conversion factor.

0.105 mol C_{8}H_{18} \times\frac{25mol O_{2}}{2molC_{8}H_{18}}  = 1.31 mol

We have 1.31 mol O₂.

Step 4 : Convert moles of O₂ to grams.

The molar mass of O₂ is 32 g/mol.

The grams of O₂ can be calculated as,

1.31 mol O_{2} \times\frac{32g}{mol}  = 42 grams

42 grams of oxygen are required.

8 0
3 years ago
How many grams of 2.5% "h" cream should be mixed with360 grams of 0.25% "h" cream to make a 1% "h" cream?
Leona [35]
Answer is: 180 <span>grams of 2.5% "h" cream should be mixed.
</span>ω₁ = 2.5% ÷ 100% = 0.025.
ω₂ = 0.25% ÷ 100% = 0.0025.
ω₃ = 1% ÷ 100% = 0.01.
m₂ = 360 g.
m₃ = m₁ + 360 g.
m₁ = ?.
ω₁ · m₁ + ω₂ · m₂ = ω₃ · m₃.
0.025 · m₁ + 0.0025 · 360 g = 0.01 · (m₁ + 360 g).
0.025 · m₁ + 0.9 g = 0.01 · m₁ + 3.6 g.
0.015 · m₁ = 2.7 g.
m₁ = 180 g.
4 0
3 years ago
Other questions:
  • The lithosphere is divided into pieces called
    10·1 answer
  • 1. What is polarity?
    6·1 answer
  • How many moles are contained in 3.131 × 1024 particles?
    10·2 answers
  • What kind of compound is salt?
    14·1 answer
  • For a given reaction, ΔH = +35.5 kJ/mol and ΔS = +83.6 J/Kmol. The reaction is spontaneous ________. Assume that ΔH and ΔS do no
    12·1 answer
  • A silver block, initially at 58.5°C, is submerged into 100.0 of water at 24.8°C in an insulated container. The final temperature
    5·1 answer
  • A mixture of iron and sulfur can be separated by attracting the Iron particles with a magnet. If the iron and sulfur mixture is
    9·1 answer
  • State the assumptions that the kinetic-molecular theory makes about the characteristics of gas particles
    12·1 answer
  • The Pi Song
    13·1 answer
  • Circle all that apply for an anion.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!