Answer:
Aluminum atoms are in 3.78 g of aluminum
02214076x10^23)8.4367659370640769254888x10^22 atoms, therefore there are 8.4367659370640769254888x10^22 atoms of Aluminum(Al) present in 3.78 grams of Aluminum(Al).
Explanation:
The answer to the question is B D E
Answer:
95 N
Explanation:
they are both pushing in the same direction so you simply add
75+20=95
In order to obtain the empirical formula, first divide each
element by its molar mass which can be found in the periodic table. The answer
in the first step would be the number of moles of each element. Then divide
each element with the lowest number of moles obtained in the first step in this
case Phosphorus had the lowest number of moles. Then round it up to the nearest
whole number. The empirical formula then is Phosphorus pentafluoride or PF5.
Answer:
dont know
Explanation:
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