Question

2 NABr + Ca(OH)2 = CaBr2 + 2 NaOH How many moles of CaB 2 are produced, if 14.72 moles of NaBr and excess Ca(OH) 2 react?

Answer 1

Answer: 7.36 moles of $CaBr_2$ will be produced.

Explanation:

We are given:

Moles of NaBr = 14.72 moles

The given chemical equation follows:

$2NaBr+Ca(OH)_2\rightarrow CaBr_2+2NaOH$

By the stoichiometry of the reaction:

2 moles of NaBr produces 1 mole of calcium bromide

So, 14.72 moles of NaBr will produce = $\frac{1}{2}\times 14.72=7.36mol$ of calcium bromide

Hence, 7.36 moles of $CaBr_2$ will be produced.