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3 years ago

2 NABr + Ca(OH)2 = CaBr2 + 2 NaOH How many moles of CaB 2 are produced, if 14.72 moles of NaBr and excess Ca(OH) 2 react?

Chemistry

1 answer:

pickupchik [31]3 years ago

4 0

<u>Answer:</u> 7.36 moles of $CaBr_2$ will be produced.

<u>Explanation:</u>

We are given:

Moles of NaBr = 14.72 moles

The given chemical equation follows:

$2NaBr+Ca(OH)_2\rightarrow CaBr_2+2NaOH$

By the stoichiometry of the reaction:

2 moles of NaBr produces 1 mole of calcium bromide

So, 14.72 moles of NaBr will produce = $\frac{1}{2}\times 14.72=7.36mol$ of calcium bromide

Hence, 7.36 moles of $CaBr_2$ will be produced.

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saveliy_v [14]

Hazardous materials are grouped into classes identifying their similarities in composition and structure.

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So we can conclude that hazardous materials are grouped into classes identifying their similarities in composition and structure.

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2 years ago

when you cook food like eggs or potatoes this is a chemical change when candle burns the wick of the candle and wax turn into no

finlep [7]

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3 years ago

Where glucose is broken down into smaller molecules to produce energy. The second part of the process takes place in the

slavikrds [6]

Answer:

Mitochondria

Explanation:

Glucose in an energy molecule contained in carbohydrate food substances. The end product of the digestion of carbohydrate is glucose which is broken down to produce energy.

The sequence of breakdown of glucose is as follows; In the first step, 6-carbon glucose is broken down into two molecules of 3-carbon pyruvic acid. This occurs in the cytoplasm of the cell. It is an anaerobic process.

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3 years ago

A certain compound has the percent composition (by mass) 85.63% C and 14.37% H. The molar mass of the compound is 42.0 g/mol. Ca

AlekseyPX

Answer:

The molecular formula is C3H6

Explanation:

Step 1: Data given

Suppose the compound has a mass of 100 grams

The compound contains:

85.63 % C = 85.63 grams C

14.37 % H = 14.37 grams H

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Step 2: Calculate moles

Moles = grams / molar mass

Moles C = 85.63 grams / 12.01 g/mol

Moles C = 7.130 moles

Moles H = 14.37 grams / 1.01 g/mol

Moles H = 14.2 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 7.130 moles / 7.130 moles = 1

H = 14.2 moles / 7.130 moles = 2

The empirical formula is CH2

The molar mass of CH2 = 14 g/mol

Step 4: Calculate molecular formula

We have to multiply the empirical formula by n

n = 42 / 14 = 3

n*(CH2) = C3H6

The molecular formula is C3H6

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3 years ago

Una sola dosis de etanol, C2 H5 OH, eleva el nivel intracelular de iones calcio. Los iones Ca2+ liberados por el etanol 0,10 M m

11Alexandr11 [23.1K]

Answer:

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Explanation:

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3 years ago